A miniscule pinhole develops in the wall of a tank, and every molecule of the gas inside that strikes the hole escapes from the pressure vessel. Calculate the number of nitrogen molecules that effuse per second through a round hole of 0.01 mm diameter if the gas is at 25 °C and one bar.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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A minuscule pinhole develops in the wall of a tank, and every molecule of the gas inside that strikes the hole escapes from the pressure vessel. Calculate the number of nitrogen molecules that effuse per second through a round hole of 0.01 mm diameter if the gas is at 25 °C and one bar.
Transcribed Image Text:A minuscule pinhole develops in the wall of a tank, and every molecule of the gas inside that strikes the hole escapes from the pressure vessel. Calculate the number of nitrogen molecules that effuse per second through a round hole of 0.01 mm diameter if the gas is at 25 °C and one bar.
Expert Solution
Step 1: Variables given

Given,

Diameter of round hole = 0.01 mm

Temperature of the gas =25 to the power of ring operator C  = (273 + 25) K = 298 K

Pressure of the gas = 1 bar = 105 pa


The process in which a gas escapes from a small hole is called effusion. Number of nitrogen molecules that effuse per second is the rate effusion. The kinetic theory of gases can be used to obtain the effusion formula as follows.

Effusion flux = P divided by left parenthesis 2 pi m K T right parenthesis to the power of 1 divided by 2 end exponentN subscript A P divided by left parenthesis 2 pi M R T right parenthesis to the power of 1 divided by 2 end exponent

Rate of Effusion = Effusion flux cross times area of the hole (Ahole)

where NA = Avogadro's constant = 6.022cross times 10 to the power of 23

 k = Boltzmann's constant

 T = Temperature in K

P = Pressure in Pascals

R = gas constant in J/(K mol) = 8.314 J/(Kmol)

M = Molar mass in kg of the material that is effusing

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