Balloon A contains neon (MM=20.2 g mol-1) at 300 K. If balloon B contains oxygen (MM=32.0 g mol-1), what temperature would balloon B have to be at so that the gases effuse at the exact same rate? Hint: The equation for the root mean square velocity is: 3RTNG Uuns. Ne MM, Ne You can write a similar equation for the gas in balloon B and set the two root mean square velocities to be equal. O 475 K O 300 K O 378 K O 238 K O 189 K

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Balloon A contains neon (MM=20.2 g mol-1) at 300 K. If balloon B contains oxygen (MM=32.0 g mol-1), what
temperature would balloon B have to be at so that the gases effuse at the exact same rate?
Hint: The equation for the root mean square velocity is:
3RTNe
V MMNe
Unus. Ne
You can write a similar equation for the gas in balloon B and set the two root mean square velocities to be equal.
475 K
300 K
O 378 K
238 K
O 189 K
Transcribed Image Text:Balloon A contains neon (MM=20.2 g mol-1) at 300 K. If balloon B contains oxygen (MM=32.0 g mol-1), what temperature would balloon B have to be at so that the gases effuse at the exact same rate? Hint: The equation for the root mean square velocity is: 3RTNe V MMNe Unus. Ne You can write a similar equation for the gas in balloon B and set the two root mean square velocities to be equal. 475 K 300 K O 378 K 238 K O 189 K
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