A military commander wants to destroy an enemy underground bunker. Each plane he sends out has a probability of 0.8 of scoring a direct hit on the bunker. It takes four direct bomb hits to penetrate the bunker and kill the enemy combatants inside. If the commander can mount seven assaults before the bunker becomes tactically unimportant, what is the probability he penetrates the bunker and eliminates the enemy combatants?
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
A military commander wants to destroy an enemy underground bunker. Each plane he sends out has a
Solution :
P = probability of scoring a direct hit on bunker = 0.8
n = no. of assaults commander can mount = 7
and 4 direct bombs penetrate the bunker and kill the enemy.
Let , X : No. of bombs required to penetrate the bunker and kill the enemy.
Here , X B ( n = 7 , p = 0.8 )
P( X=x ) = ; x = 0,1,2,...., 7
=
Therefore probability that military commander penetrate the bunker and eliminates the enemy combatants is,
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
