A microscope slide 10. cm long is separated from a glass plate at one end by a sheet of paper, the other end of the slide is in contact with the plate. The slide is illuminated from above by light from a sodium lamp (λ=589nmλ=589nm). 1. Is the first fringe near the edge where the plates are in contact a bright fringe or a dark fringe? Select the best answer and explanation. a. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change ππ and reflection from the lower interface causes phase change 00, the path difference brings the two reflected waves back into phase. b. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ, but the path difference causes the two reflected waves to be maximally out of phase. c. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change 00, but the path difference causes the two reflected waves to be maximally out of phase. d. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change 00 while the path difference is approximately zero. e. The first fringe is dark because reflection from the upper interface of the air gap causes phase change ππ while reflection from the lower interface causes phase change 00 while the path difference is approximately zero. f. The first fringe is dark because reflection from the upper interface of the air gap causes phase change 00 while reflection from the lower interface causes phase change ππ while the path difference is approximately zero. g. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change 00 and reflection from the lower interface causes phase change ππ, the path difference brings the two reflected waves back into phase. h. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ while the path difference is approximately zero.
A microscope slide 10. cm long is separated from a glass plate at one end by a sheet of paper, the other end of the slide is in contact with the plate. The slide is illuminated from above by light from a sodium lamp (λ=589nmλ=589nm). 1. Is the first fringe near the edge where the plates are in contact a bright fringe or a dark fringe? Select the best answer and explanation. a. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change ππ and reflection from the lower interface causes phase change 00, the path difference brings the two reflected waves back into phase. b. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ, but the path difference causes the two reflected waves to be maximally out of phase. c. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change 00, but the path difference causes the two reflected waves to be maximally out of phase. d. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change 00 while the path difference is approximately zero. e. The first fringe is dark because reflection from the upper interface of the air gap causes phase change ππ while reflection from the lower interface causes phase change 00 while the path difference is approximately zero. f. The first fringe is dark because reflection from the upper interface of the air gap causes phase change 00 while reflection from the lower interface causes phase change ππ while the path difference is approximately zero. g. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change 00 and reflection from the lower interface causes phase change ππ, the path difference brings the two reflected waves back into phase. h. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ while the path difference is approximately zero.
Related questions
Question
A microscope slide 10. cm long is separated from a glass plate at one end by a sheet of paper, the other end of the slide is in contact with the plate. The slide is illuminated from above by light from a sodium lamp (λ=589nmλ=589nm).
1. Is the first fringe near the edge where the plates are in contact a bright fringe or a dark fringe? Select the best answer and explanation.
| a. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change ππ and reflection from the lower interface causes phase change 00, the path difference brings the two reflected waves back into phase. |
| b. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ, but the path difference causes the two reflected waves to be maximally out of phase. |
| c. The first fringe is dark because reflection from each the upper and the lower interfaces of the air gap causes phase change 00, but the path difference causes the two reflected waves to be maximally out of phase. |
| d. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change 00 while the path difference is approximately zero. |
| e. The first fringe is dark because reflection from the upper interface of the air gap causes phase change ππ while reflection from the lower interface causes phase change 00 while the path difference is approximately zero. |
| f. The first fringe is dark because reflection from the upper interface of the air gap causes phase change 00 while reflection from the lower interface causes phase change ππ while the path difference is approximately zero. |
| g. The first fringe is bright because, while reflection from the upper interface of the air gap causes phase change 00 and reflection from the lower interface causes phase change ππ, the path difference brings the two reflected waves back into phase. |
| h. The first fringe is bright because reflection from each the upper and the lower interfaces of the air gap causes phase change ππ while the path difference is approximately zero. |
2. Suppose that the setup of the preceding problem is immersed in an unknown liquid. If 19 fringes per centimeter are now seen along the slide, what is the index of refraction, nn of the liquid?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
