A thin film of oil is on a puddle of water. Light of wavelength 635nm hits the thin film. What minimum thickness of oil will give constructive interference of the reflected light? n =1.00, n =1.50, naler =1.33 'air water
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- m, and d= 3.00 x 10 m. (B) Determine the distance between adjacent bright fringes. Use the bright fringe equation again to find the distance between any adjacent bright fringes (here, those characterized by m and m + 1). AL AL (m+ 1) - AL Ay = y+1 m%3D (5.63 x 107 m)(1.20 m) - 2.25 cm 3.00 x 105 m LEARN MORE REMARKS This calculation depends on the angle 0 being small because the small angle approximation was implicitly used. The measurement of the position of the bright fringes yields the wavelength of light, which in turn is a signature of atomic processes, as is discussed in the chapters on modern physics. This kind of measurement therefore helped open the world of the atom. QUESTION Which of the following make the separation between fringes greater in the two slit interference experiment? (Select all that apply.) O Larger separation of the two slits. O Narrower slits. Wider slits. O Smaller separation of the two slits. PRACTICE IT Use the worked example above to help you solve this…White light is directed perpendicular to an oil film (n = 1.45). Calculate the minimum non-zero thickness of the film required to eliminate blue (450nm) reflections.Mourning doves have a small batch of iridescent feathers. The color isproduced by a 260-nm-thick layer of keratin (n = 1.56), with air on both sides that are found around the edge of the feather barbules. For what visible wavelength (or wavelengths) would this structure produce constructive interference? A) 686nm, 412nmB) 406nmC) 686nm, 541nm, 412nmD) 541nmE) 1622nm, 811nm, 270nm
- A light with wavelength λ = 565 nm falls on a pair of closely separated slits. The first dark fringe of the interference pattern is at an angle θ = 3.25 degrees from the central maximum. a) Solve for the numerical value of d in mm.Yellow light (Ao = 560 nm) is NOT reflected in air by a thin film deposited on glass. If the thickness of the film is 100 nm and glass has a refractive index of nglass = 1.50, what is a possible value for the refractive index of the thin film? nair 1.00 100 nm Nthin film Nglass 1.50 O A. 1.1 оВ. 1.2 О С. 1.3 O D. 1.4A thin film of oil is on water. What is the thinnest that the oil can be to have constructive interference on reflection? The wavelength of the light in air is 480nm. Assume the beam starts in air. [n =1.00 ,n =1.50 , nwaer =1.33]
- A thin film of oil (n 1.45) is floating on a water surface (n = 1.33) and is illuminated from above by monochromatic light (A = 590 nm). For what thickness of the oil film will the reflected light be bright? (in nm) = OA: 48.3 OB: 60.4 OC: 75.5 OD: 94.4 OE: 118.0 OF: 147.5 OG: 184.4 OH: 230.5Green light of wavelength 550 nm passes through a diffraction grating with a slit spacing of 0.001 mm and makes an interference pattern on the wall. How many bright fringes will be seen? А. 1 В. 3 С. 5 D. 7A single slit of width 4.50 x 10 ºm produces a first-order dark fringe at some angle. If the width of the slit is now changed to 3.08 × 10-ºm, a second-order dark fringe is found at three times the previous angle. What is the wavelength of the light?
- A monochromatic (single wavelength) light is incident on a 0.12-mm-wide slit. The second minimum in the diffraction pattern occurs at 0.70⁰. a. What is the wavelength of the incident light? b. If the screen on which the diffraction pattern is produced is placed 0.8 m away from the slit, determine the width of the central maximum.When green (550 nm) light is shone through a double slit the angle of the first dark fringe is 1.9 degrees. Calculate the angle in degrees of the second dark fringe.