A metal strip 7.00 cm long, 0.82 cm wide, and 0.71 mm thick moves with constant velocity (v) through a uniform magnetic field B = 1.10 mT directed perpendicular to the strip. A potential difference of 3.50 µV is measured across the width of the strip. What is the speed v? m/s V= What potential difference would be measured across the width of the strip if the velocity is 1.9 m/s? AV = μV X X X X X X X X X X X X X x X: X X W X X 100 B X X X X X length
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- A metal strip 9.11 cm long, 0.864 cm wide, and 0.660 mm thick moves with constant velocity through a uniform magnetic field B = 1.77 mT directed perpendicular to the strip, as shown in the figure. A potential difference of 4.29 μV is measured between points x and y across the strip. Calculate the speed v. Number i Units X XAn electron moves in a circular part perpendicular to the earth’s 3.5 x 10 ^-5 T magnetic field.The radius of the circle is 0.70 m. Calculate the electron’s speed.1. An alpha-particle (m = 6.64-10-27 kg; q = 3.2.10-19 C) travels in a circular path of radius 30 cm in a uniform magnetic field of magnitude 1.8 T. (a) What is the speed of the particle? m/s V= (b) What is the kinetic energy in electron-volts? KE= eV (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy? V= V Hint: What is the relationship between electric potential energy and electric potential? What is the relationship between the change in kinetic energy and the change in the potential energy of the alpha particle? 0
- In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.470 cm thick is positioned along an east-west direction. Assume n = 8.46 x 1028 electrons/m3 and the plane of the bar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the conductor results in a Hall voltage of 5.15 x 10-12 v, what is the magnitude of the Earth's magnetic field at this location? µT Need Help? Read It Master It0.15 T along a direction perpendicular to the field. What is the radius of the circular path of the ion in the magnetic field? (Units: cm)Consider a straight conductor of length 6.3 cm. The conductor moves at right angles to a magnetic field of uniform strength B = 10-3 T generating e.m.f. of 2.5 × 10-5 v. Calculate the velocity of the straight conductor. Give your answer in SI units. Answer: Choose... + Next page Previous page
- Consider the mass spectrometer shown schematically in the figure below. The magnitude of the electric field between the plates of the velocity selector is 2.20 x 10³ V/m, and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.0300 T. Calculate the radius of the path for a singly charged ion having a mass m = 1.86 x 10-26 kg. x Need Help? X X P X m x x * % X x Detector array Velocity selector Bo, in X Read It X x X X É x x X X 100 V **** +9 Watch It X * x x * * * X x x XIn the figure (Figure 1) a conducting rod of length L = 31.0 cm moves in a magnetic field B of magnitude 0.480 T directed into the plane of the figure. The rod mc with speed v = 5.30 m/s in the direction shown. Figure X X X X X b X χαχ X X 1 of 1 X X X What is the potential difference between the ends of the rod? Express your answer in volts. NO | ΑΣΦΑ ▼ V = Submit Part B Which point, a or b, is at higher potential? b Submit Part C Request Answer E = Submit Request Answer When the charges in the rod are in equilibrium, what is the magnitude of the electric field with Express your answer in volts per meter. VG ΑΣΦΑ V Request Answer V/mThe Hall effect can be used to determine the density of mobile electrons in a conductor. A thin strip of the material being investigated is immersed in a magnetic field and oriented so that its surface is perpendicular to the field. In a particular measurement, the magnetic field strength was 0.723 T, the strip was 0.107 mm thick, the current along the strip was 2.83 A, and the Hall voltage between the strip's edges was 2.73 mV. Find the density n of mobile electrons in the material. The elementary charge is 1.602 x 10-1° C. n = -3 m
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