A metal rod of length 0.1 m as shown in Figure 1 that is initially at 70°C,that is the temperatures of all he nodes inside the rod when time is zero. The steady-state temperature at the left and right ends of he rod is given by 50°C and 20°C, respectively. Use the implicit method to find the temperature distribution in the rod from t = 0 to t = 10 seconds. Use the Ax = 0.01 m, k = 54W/m-K, = 7800kg/m3 and C = 490 J/kg-K. Determine value of and to solve the temperature distribution for the time as i) and i). Then, solve using direct method and Gauss-Seidel method. Compare the error between the exact solution and iterative method. At = 1 s ) At = 2 s

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A metal rod of length 0.1 m as shown in Figure 1 that is initially at 70°C,that is the temperatures of all
the nodes inside the rod when time is zero. The steady-state temperature at the left and right ends of
the rod is given by 50°C and 20°C, respectively. Use the implicit method to find the temperature
distribution in the rod from t = 0 to t = 10 seconds. Use the Ax = 0.01 m, k = 54W/m-K, = 7800kg/m3
and C = 490 J/kg-K. Determine value of and to solve the temperature distribution for the time as i)
and i). Then, solve using direct method and Gauss-Seidel method. Compare the error between the
exact solution and iterative method.
1) At = 1s
i) At = 2 s
IV = 70°C
BVight = 20 C
BV = 50C
0.1 m
Transcribed Image Text:A metal rod of length 0.1 m as shown in Figure 1 that is initially at 70°C,that is the temperatures of all the nodes inside the rod when time is zero. The steady-state temperature at the left and right ends of the rod is given by 50°C and 20°C, respectively. Use the implicit method to find the temperature distribution in the rod from t = 0 to t = 10 seconds. Use the Ax = 0.01 m, k = 54W/m-K, = 7800kg/m3 and C = 490 J/kg-K. Determine value of and to solve the temperature distribution for the time as i) and i). Then, solve using direct method and Gauss-Seidel method. Compare the error between the exact solution and iterative method. 1) At = 1s i) At = 2 s IV = 70°C BVight = 20 C BV = 50C 0.1 m
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