A metal ion in a high-spin octahedral complex has two more unpaired electrons than the same ion does in a low-spin octahedral complex. Which of the following could the metal ion be? 1. Ti²+ 2. Cu²+ 3. Mn2+ 4. CO³+ 5. Co²+
A metal ion in a high-spin octahedral complex has two more unpaired electrons than the same ion does in a low-spin octahedral complex. Which of the following could the metal ion be? 1. Ti²+ 2. Cu²+ 3. Mn2+ 4. CO³+ 5. Co²+
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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
Transcribed Image Text:**Question:**
A metal ion in a high-spin octahedral complex has two more unpaired electrons than the same ion does in a low-spin octahedral complex. Which of the following could the metal ion be?
1. Ti²⁺
2. Cu²⁺
3. Mn²⁺
4. Co³⁺
5. Co²⁺
**Discussion:**
In octahedral complexes, the arrangement of electrons depends on whether the complex is high-spin or low-spin. High-spin complexes occur when the crystal field splitting energy (Δ₀) is less than the pairing energy, leading to a larger number of unpaired electrons. Conversely, low-spin complexes occur when the crystal field splitting energy (Δ₀) is greater than the pairing energy, resulting in fewer unpaired electrons.
To determine which metal ion is described:
- High-spin octahedral complexes will have more unpaired electrons compared to low-spin octahedral complexes.
- The difference in unpaired electrons between high-spin and low-spin states must be two.
**Solution Explanation:**
1. **Ti²⁺** (3d²):
- High-spin: 2 unpaired electrons
- Low-spin: Not applicable (no significant difference in a 3d² configuration)
2. **Cu²⁺** (3d⁹):
- High-spin: 1 unpaired electron
- Low-spin: 1 unpaired electron (no difference)
3. **Mn²⁺** (3d⁵):
- High-spin: 5 unpaired electrons
- Low-spin: 1 unpaired electron
- Difference: 4 unpaired electrons (not 2, so it doesn't fit)
4. **Co³⁺** (3d⁶):
- High-spin: 4 unpaired electrons
- Low-spin: 2 unpaired electrons
- Difference: 2 unpaired electrons (fits the condition)
5. **Co²⁺** (3d⁷):
- High-spin: 3 unpaired electrons
- Low-spin: 1 unpaired electron
- Difference: 2 unpaired electrons (also fits the condition)
From the given options, Co³⁺ and Co²⁺ meet the criteria where the high-spin state has two more unpaired electrons than the low-spin state.
**Correct Answer:
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