A metal fabricator produces connecting rods with an outer diameter that has a 1± 0.02 inch specification. A machine operator takesseveral sample measurements over time and determines the sample mean outer diameter to be 1.005 inches with a standard deviationof 0.003 inch.Calculate the process capability index for this example.Note: Round your answer to 3 decimal places.Process capability index

Given:standar deviation (σ)=0.003sample mean (x̄)=1.005Upper Specification Limit (USL)=…

Answered: A metal fabricator produces connecting…

Understanding Business

12th Edition

ISBN:9781259929434

Author:William Nickels

Publisher:William Nickels

Chapter1: Taking Risks And Making Profits Within The Dynamic Business Environment

Section: Chapter Questions

Problem 1CE

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Boxes of Honey-Nut Oatmeal are produced to contain 14.0 ounces, with a standard deviation of 0.10 ounce. For a sample size of 49, the 3-sigma x chart control limits are: Upper Control Limit (UCL) = Lower Control Limit (LCL) = ounces (round your response to two decimal places). ounces (round your response to two decimal places).
C-Spec, Incorporated is attempting to determine whether an existing machine is capable of milling an engine part that has a key specification of 4 ± 0.003 inch. After a trial run on this machine, C-Spec has determined that the machine has a sample mean of 4.001 inches with a standard deviation of 0.002 inch. Calculate the capability index ( Cpk�� ) for this machine. Note: Round your answer to 3 decimal places. Should C-Spec use this machine to produce this part? multiple choice Yes No
2) The specification for a Lindemann’s stainless steel chimney liner requires a thickness of 7.1 mm ± 0.1 mm. The firm’s quality analyst determines that the liner process operates at a mean thickness of 7.13 mm with the standard deviation of the process being 0.02 mm. a) Calculate the upper and the lower limits for the stainless steel chimney liner. b) Calculate the Cpand Cpkfor this process. Hint: Cp = (Upper Specification Limit – Lower Specification Limit)/6sigma Cpk = minimum of [(Upper Specification Limit – Xbar)/3sigma], [(Xbar – Lower Specification Limit)/3sigma]
An operator wants to determine the standard deviation for a machine she operates. To do this, she wants to create a p-chart. Over a month's time, she collects 30 samples of 75 observations each and records the number of errors. The average proportion defective is found to be 0.024. Which of the following is the standard deviation () of the machine? a. More than 0.5 but less than or equal to 1.0 b. More than 1.0 c. Less than or equal to 0.1 d. More than 0.1 but less than or equal to 0.5
Linda Boardman, Inc., an equipment manufacturer in Boston, has submitted a sample cutoff valve to improve your manufacturing process. Your process engineering department has conducted experiments and found that the valve has a mean of 8.00 and a standard deviation of .04. Your desired performance is = 8.0 ± 30, where o = 0.047. Is the following statement true or false? Can Boardman produce the valve within the specified tolerance? (TRUE=yes, it can; FALSE=no, it cannot) O True O False
A process sampled 20 times with a sample of size 8 resulted in = 28.5 and R = 1.8. Compute the upper and lower control limits for the chart for this process. (Round your answers to two decimal places.) UCL = LCL = Compute the upper and lower control limits for the R chart for this process. (Round your answers to two decimal places.) UCL = LCL =
Refer to Table 56.1-Factors for Computing Control Chart Limits.(3.sigma) for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? mm (round your response to two decimal places). b) What is the value of R? R=mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Day 1 2 3 4 5 Upper Control Limit (UCL;)mm (round your response to two decimal places) Lower Control Limit (LCL;)mm (round your response to two decimal places). d) What are the UCL and LCL using 3-sigma? Upper Control Limit (UCLR)-mm (round your response to two decimal places). Lower Control Limit (LCL)-mm (round your response to two decimal places) Mean x (mm) 154.9 151.2 155.6 155.5 154.6 Range R (mm) 4.4 4.8 4.3 5.0 4.7 Next
S Book Hint Print eferences Problem 13-2 (Algo) A metal fabricator produces connecting rods with an outer diameter that has a 1 ± 0.02 inch specification. A machine operator takes several sample measurements over time and determines the sample mean outer diameter to be 1.004 inches with a standard deviation of 0.006 inch. Calculate the process capability index for this example. (Round your answer to 3 decimal places.) Process capability index
7. An ad agency tracks the complaints, by week received, about the billboards in its city: Week No. of Complaints 1 3 2 6 3 4 4 12 5 2 6 9 This exercise contains only parts a, b, and c. Part 2 a) The type of control chart that is best to monitor this process is c minus chart ______ . Part 3 b) Using z = 3, the control chart limits for this process are (assume that the historical complaints rate is unknown): UCLc = ________ complaints per week (round your response to two decimal places). The upper control limit is: ________ The lower control limit is: _________ The central limit is ___________
Twelve samples, each containing five parts, were taken from a process that produces steel rods at Emmanual Kodzi's factory. The length of each rod in the samples was determined. The results were tabulated and sample means and ranges were computed. The results were: Sample Sample Mean (in.) Range (in.) Sample Sample Mean (in.) Range (in.) 1 11.404 0.044 7 11.403 0.021 2 11.400 0.051 8 11.407 0.058 3 11.389 0.042 9 11.397 0.039 4 11.406 0.037 10 11.403 0.038 5 11.395 0.048 11 11.401 0.054 6 11.397 0.053 12 11.406 0.061 Part 2 For the given data, the x = enter your response here inches (round your response to four decimal places). The control limits for the 3-sigma R-chart are (round all intermediate calculations to three decimal places before…
A control chart for fraction nonconforming is to be established using a center line of p=0.03. What sample size is required if we wish to detect a shift in the process fraction nonconforming to 0.08 with probability 0.50? 1269 475 73 316 216 2 105 150 265
An insurance company samples claim forms for errors created by its employees as well as the amount of time it takes to process a claim. a. When the process is in control, the proportion of claims with an error is .033. A p chart has LCL = 0 and UCL = .068. Plot the following seven sample results: .035, .062, .055, .049, .058, .066, and .055. Comment on whether there might be concern about the quality of the process.

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