ab Statistid Amedical researcher says that less than 79% of adults in a certain country think that healthy children should be required to be vaccinated. In a random sample of300 adults in that country, 75% think that healthy children should be required to be vaccinated. At a= 0.01, is there enough evidence to support the researcher'sclaim? Complete parts (a) through (e) below.Identify the critical value(s) for this test.=-2.33(Round to two decimal places as needed. Use a comma to separate answers as needed.)Identify the rejection region(s). Select the correct choice below and fill in the answer box(es) to complete your choice.(Round to two decimal places as needed.)ddr. Teecher es. every timegs an argel ge1s his winga."OA The rejection region is z>y CoursesOB. The rejection regions are z<and z>ourse Home&c. The rejection region isz< -2.33OD. The rejection region isAssignments(c) Find the standardized test statistic z.Gradebook(Round to two decimal places as needed.)Chapter Contentst: 0еТеxtHelp me solve thisView an exampleGet more help-Clear allCheck answerMultimedia LibraryStudy Plan47°F A @ aO Type here to search+6610/05/1775DeletePrtScInsertF11F12F10

The formula to find the standardized z - test statistic for testing the significance of one…

Answered: A medical researcher says that less…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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10% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 369 people from the inner city surveyed, 22 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: Ho: ? μ p Select an answer = < ≠ > (please enter a decimal) H1: ? μ p Select an answer > ≠ < = (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 10% at αα = 0.01, so…
20% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 356 randomly selected students who receive financial aid, 61 of them volunteered their time. What can be concluded at the αα = 0.10 level of significance? For this study, we should use? Select an answer z-test for a population proportion? or t-test for a population mean? The null and alternative hypotheses would be: H0:H0:? μ or p Select an answer ≥ = < > ≤ ≠ _______(please enter a decimal) H1:H1:? μ or p Select an answer ≥ ≠ = < > ≤ _______ (Please enter a decimal) 2. The test statistic ? t or z = ______ (please show your answer to 3 decimal places.) The p-value = ______ (Please show your answer to 4 decimal places.) The p-value is ? > or ≤ α 3. Based on this, we should Select an answer fail to reject? reject ? accept ? the null…
Researchers wanted to know if therapy could help smokers quit smoking. Of the 71 smokers they tested, 39 were smoking one year after treatment. Use a 0.05 significance level to test the claim that the majority are smoking one year after treatment. What is/are the critical value(s)? ттT Arial 3 (12pt) v TE -E · -
The recidivism rate for convicted sex offenders is 13%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 309 convicted sex offenders who were also drug addicts, 31 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is ? va Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 13% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
The recidivism rate for convicted sex offenders is 11%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 337 convicted sex offenders who were also drug addicts, 30 of them became repeat offenders. What can be concluded at the a = 0.10 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? ✓ Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is? ♥ α Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 11% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
The mean height of a certain kind of plant is 170 centimeters. Suppose we want to carry out a hypothesis test to see if the mean height when these plants are treated with a certain chemical differs from 170. State the null hypothesis H0 and the alternative hypothesis H1 that we would use for this test.
A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 7.45 and the critical Chi square is 9.488. What may be concluded? Group of answer choices A.reject the null hypothesis, church attendance and marital status are independent B.fail to reject the null hypothesis, church attendance and marital status are independent C.Reject the null hypothesis, church attendance and marital status are dependent D.fail to reject the null hypothesis, church attendance and marital status are dependent
The effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?
please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…
Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…
Identify the z* critical value for constructing a confidence interval for one proportion using these confidence levels. You can reference the tdistribution table to answer this question. Enter each answer to 3 decimal places. 90% confidence: 95% confidence: 99% confidence:

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