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- Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 150 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.05 level of significance. What are the null and alternative hypotheses? = 0.03 versus H,: p Ho: P (Type integers or decimals. Do not round.) 0.03 Because npo (1- Po) = || V 10, the normal model (Round to one decimal place as needed.) V be used to approximate the P-value.According to the Oxnard College Student Success Committee report in the previous year, we believe that 23% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 99% confident that your estimate is within 2.5% of the true population proportion. How large of a sample size is required? Do not round mid-calculation.n =According to the Oxnard College Student Success Committee report in the previous year, we believe that 20% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 95% confident that your estimate is within 2% of the true population proportion. How large of a sample size is required? Do not round mid-calculation. n =
- A magazine claims that the brand of shoe you buy can have a major impact on how fast you run. A researcher decides to test this assertion and gathers a group of seven (N=7) runners and asks each of them to run a mile wearing each of the four different types of shoes (Nike, Adidas, Asics, and Brooks) and records how quickly the runners complete their miles wearing each type of shoe. Conduct a within subjects (AKA repeated measures) ANOVA, at alpha = 0.05, to see if the runners mile times are significantly different depending on the type of shoe they wear. Identify the correct alternative hypothesis A. At least two mean mile times are different from at least two other mean mile times between the four different types of shoes being tested B. There is a significant difference in mean mile time between the four different types of shoes being tested C. At least one mean mile time is different from at least two other mean mile times between the four different types of shoes being…A sample of 60 chewable vitamin tablets have a sample mean of 298 milligrams of vitamin C. Nutritionists want to perform a hypothesis test to determine how strong the evidence is that the mean mass of vitamin C per tablet differs from 299 milligrams. State the appropriate null and alternate hypotheses.A risky eye surgery for patients in danger of permanent blindness is known to historically cure the condition in 35% of all cases of performing the surgical procedure. A new procedure is proposed for which the researchers claim that they will improve that rate of cure. -Write an appropriate null and alternate hypothesis for the researchers to test their claim.
- Previously, 5% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 5% today. She randomly selects 150 pregnant mothers and finds that 5 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.05 level of significance. What are the null and alternative hypotheses? = 0.05 versus H,: p < 0.05 Ho: P (Type integers or decimals. Do not round.) Because npo (1- Po) = [ (Round to one decimal place as needed.) V 10, the normal model V be used to approximate the P-value.On average, 0(zero) is expected for the t statistic when the null hypothesis is true. Why? The value for an unknown population mean is estimated with a confidence interval using the t statistic? Why?According to the Oxnard College Student Success Committee report in the previous year, we believe that 17% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 95% confident that your estimate is within 1% of the true population proportion. How large of a sample size is required? Do not round mid-calculation. n =
- just the last part thank you!Previously, 4% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 4% today. She randomly selects 135 pregnant mothers and finds that 4 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a= 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.04 versus H,: p < 0.04 (Type integers or decimals. Do not round.) Because npo (1- Po) =U (Round to one decimal place as needed.) 10, the normal model be used to approximate the P-value.Previously, 5% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 5% today. She randomly selects 140 pregnant mothers and finds that 5 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.05 level of significance. What are the null and alternative hypotheses? < 0.05 Họ: p = 0.05 versus H,: p (Type integers or decimals. Do not round.) Because npo (1- Po) < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)