A mass weighing 4lb stretches a spring 8 in. If the mass is pushed upward, contracting the spring a distance of 8 in and then set in motion with a downward velocity of 6 ft/s, and if there is no damping and no other external force on the system, find the position u of the mass at any time t. Determine the frequency (wo), period (T), amplitude (R), and phase (8) of the motion. NOTE: Enter exact answers. Use t as the independent variable. u(t)
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- A mass weighing 5 lb stretches a spring 4in. If the mass is pushed upward, contracting the spring a distance of 5 in and then set in motion with a downward velocity of 3 ft/s, and if there is no damping and no other external force on the system, find the position u of the mass at any time t. Determine the frequency (wo), period (T), amplitude (R), and phase (8) of the motion. NOTE: Enter exact answers. Use t as the independent variable. u(t) wo rad/s T = R = ft rad || ||A spring/mass/dashpot system has mass 5 kg, damping constant 70 kg/sec and spring constant 845 kg/sec/sec. Express the ODE for the system in the form a"+ 2px' + wr = 0 Identify the natural (undamped) frequency of the spring: wo 3= (square Hz) Identify the parameter p: (Hz) Now assume that the system has the oscillating forcing function cos(wod) with the same frequendy as the spring's natural frequency. + 14a'+ 169a = cos(wat) Find the general solution.Given a horizontal spring, an object with a mass of 5 kg is pulled to the right 15 cm to the right. (Observation was made that during 8 seconds 12 oscialtions occured druing the trial). Find the postion and velocity after 1-second. Use equation: x(t) = Acos(wt +phi) where A is max amplitude w is angular frequency t is time and phi is phase
- A force of 5 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then immersed in a medium that offers a damping force numerically equal to 1.6 times the instantaneous velocity. (a) Find the equation of motion if the mass is initially released from rest from a point 1 foot above the equilibrium position. x(t) = (b) Express the equation of motion in the form x(t) } = Ae-¹t sin(√√w² - 2²t + $) which is given in (23) of Section 3.8. (Round to two decimal places.) x(t) = ft ft S (c) Find the first time at which the mass passes through the equilibrium position heading upward. (Round your answer to three decimal places.)3 b) A mass weighing 4 pounds is attached to a spring whose constant is 2 Ib/ft. The medium offers a damping force that is numerically equal to the instantaneous velocity. The mass is initially released from a point 1 foot above the equilibrium position with a downward velocity of 14 ft/s. Find the time (in s) at which the mass attains its extreme displacement from the equilibrium position (the extreme distance after passing the equilibrium position.) Round your answer to two digits after the decimal sign.A disk of radius 0.25 meters is attached at its edge to a light (massless) wire of length 0.50 meters to form a physical pendulum. Assuming small amplitude motion, calculate its period of oscillation. For a disk, I = (1/2)MR2 about its center of mass.
- A horizontal spring mass system oscillates on a frictionless plane. At time t=0, it is moving left at position x=9 cm. It has velocity v=0, at positions x=0 cm and 12 cm, and completes one full cycle in 2 seconds. Write the position and velocity kinematic equations for this oscillating system, including the phase constant.A block of mass M attached to a spring of constant k, oscillates back and forth with am- plitude A. At the instant when the block is at its maximum amplitude a lump of putty of mass m is dropped from a small height and sticks to the block. The mass of the spring is negligible and the surface on which M moves is frictionless. Which of the following statements is true regarding the amplitude of the oscillations? The amplitude decreases because the inelastic collision removes energy from the system The amplitude decreases because the spring must now move a larger total mass O The amplitude remains the same because m does not change the energy of the system O The amplitude increases because m adds potential energy to the system O The amplitude remains the same because the maximum kinetic energy does not change