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A mass of 15 kilograms stretches the spring 0.5 meters. Use this information to find the spring constant (use g = 9.81 m/s² as the acceleration of gravity). k = 294 OB The previous mass is detached from the spring and a mass of 8 kilograms is attached. This mass is displaced 0.55 meters below equilibrium and then launched with an initial velocity of 0.5 meters/second. Find the equation of motion. Note: When solving this problem, consider positions below equilibrium to be positive. 7√3t 7√3t sin 11 cos x(t) 2 2 7√3 20 X

A mass of 15 kilograms stretches the spring 0.5 meters. Use this information to find the spring constant (use g = 9.81 m/s² as the acceleration of gravity). k = 294 OB The previous mass is detached from the spring and a mass of 8 kilograms is attached. This mass is displaced 0.55 meters below equilibrium and then launched with an initial velocity of 0.5 meters/second. Find the equation of motion. Note: When solving this problem, consider positions below equilibrium to be positive. 7√3t 7√3t sin 11 cos x(t) 2 2 7√3 20 X

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A mass of 15 kilograms stretches the spring 0.5 meters. Use this information to find the spring constant (use g - 9.81 m/s² as the acceleration of gravity). = k - 294 The previous mass is detached from the spring and a mass of 8 kilograms is attached. This mass is displaced 0.55 meters below equilibrium and then launched with an initial velocity of 0.5 meters/second. Find the equation of motion. Note: When solving this problem, consider positions below equilibrium to be positive. sin 7√3t 2 11 cos 7√3t 2 x(t): X 7√3 20
Transcribed Image Text:A mass of 15 kilograms stretches the spring 0.5 meters. Use this information to find the spring constant (use g - 9.81 m/s² as the acceleration of gravity). = k - 294 The previous mass is detached from the spring and a mass of 8 kilograms is attached. This mass is displaced 0.55 meters below equilibrium and then launched with an initial velocity of 0.5 meters/second. Find the equation of motion. Note: When solving this problem, consider positions below equilibrium to be positive. sin 7√3t 2 11 cos 7√3t 2 x(t): X 7√3 20
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