A mass ma 3.0 kg, moving with velocity V=(4.01 + 8.01 - 2.0k)m/s, collides with mass ms = 4.0 kg, which is initially at rest. Immediately after the collision, mass ma is observed traveling at velocity VA (-2.01 + 2.0k)m/s. Find the velocity of mass me after the collislon In m/s. (Assume no outside force acts on the two masses during the collision.) %3D %3D

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Chapter1: Units, Trigonometry. And Vectors
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A mass ma =3.0 kg, moving with velocity V=(4.01+ 8.0j -2.0k)m/s, collides with mass ms = 4.0 kg,
which Is initially at rest. Immediately after the collision, mass ma is observed traveling at velocity VA:
(-2.01 + 2.0k)m/s. Find the velocity of mass me after the collislon in m/s. (Assume no outside force acts on
the two masses during the collision.)
%3D
%3D
Option 1
Option 2
Option 3
(4.0f +3.3f-3.3k) (4.51+ 6.0f- 3.0k) (2.51 +4.0) (2.01 +4.0 +3.ok) (7.0j+5.0k)
Option 4
Option 5
Transcribed Image Text:A mass ma =3.0 kg, moving with velocity V=(4.01+ 8.0j -2.0k)m/s, collides with mass ms = 4.0 kg, which Is initially at rest. Immediately after the collision, mass ma is observed traveling at velocity VA: (-2.01 + 2.0k)m/s. Find the velocity of mass me after the collislon in m/s. (Assume no outside force acts on the two masses during the collision.) %3D %3D Option 1 Option 2 Option 3 (4.0f +3.3f-3.3k) (4.51+ 6.0f- 3.0k) (2.51 +4.0) (2.01 +4.0 +3.ok) (7.0j+5.0k) Option 4 Option 5
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