A market researcher for a consumer electronics company wants to study the media viewing behaviour of residents of aparticular area. A random sample of 40 respondents is selected, and each respondent is instructed to keep a detailed record oftime spent engaged viewing content across all screens in a particular week.The results are asfollows: Content viewing time perweek: Sample mean X-bar = 38 hours, S-5.9 hours.Construct a 99% confidence interval estimate for the mean content viewing time per week in this area

Answer: From the given data, sample size(n) = 40 sample mean(x¯) = 38 Standard deviation(s) = 5.9…

Answered: A market researcher for a consumer…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the 99% Confidence Interval for mean time (in hours) spent per day engaging media for UCLA students. Do this "by hand", using appripriate symbols/formulas/tables.
A major company would like to assess the impact of using a professional trainer to conduct a confidence-building workshop with its salespeople. A sample of 16 workers is obtained. Half (n = 8) attend the workshop and the other half (n = 8) serve as a control group. Two weeks later, each of the participants is given a questionnaire measuring the level of self-confidence. The data are as follows: Controls Workshop M = 17.5 M = 22.7 SS = 100 SS = 124 What type of t-test would you have to conduct in this scenario? Are the data sufficient to conclude that the treatment has a significant effect? Use a two-tailed test with α = .05. State the hypothesis, find the critical region, calculate your test statistic, evaluate your hypothesis then calculate the Cohen’s d measure for this scenario. State whether this is a weak, moderate, or strong effect.
create a 90% confidence interval for the following data: x = 25 n = 100
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A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the calculator steps to find standard deviaton, rounded to 3 decimal places?
An online retailer has identified the maximum willingness of 10 consumers to pay for the same product. The 10 prices are: $10.00, $11.50, $9.50, $10.20, $11.20, $10.50, $9.80, $10.10, $9.90, $11.00 The retailer seeks a 95% confidence interval for the mean price consumers are willing to pay. The sample mean is calculated as $10.37, and the sample standard deviation is $0.66. Also consider the following t-values: Degrees of freedom 8 a. (9.99, 10.75) 9 10 90% confidence 1.86 1.833 1.812 95% confidence 2.306 2.262 2.228 99% confidence 3.355 3.250 3.169 Selecting the correct t-value, calculate the limits of the confidence interval.
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