A market research business is interested in testing the hypothesis that the proportion of students who own a car is smaller for the local university campus than for the local private college. They interviewed 240 students from the university and 250 students from the private college. The number of students who owned a car was 162 at the university and 183 at the private college. Construct a 99% confidence interval for the difference in the true proportions of students who own cars at the two campuses (rounded off to three decimals).

Q: A survey administered in a certain socioeconomic group gathered information to assess self-esteem of…

A:

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: A Pew Internet Project Data Memo presented data comparing adult gamers with teen gamers with respect…

A: Given : p̂1 = 0.54 p̂12 = 0.89 n1 = 1063 n2 = 1064

Q: f n=450 and X = 360, construct a 99% confidence interval.

A:

Q: Researchers in a statistics course at a Texas college wanted to investigate the optimism in…

A: Given that, The objective of the research study was to investigate the optimism in receiving a job…

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: In a survey of 3084 adults aged 57 through 85 years it was found that 81.9% of them used at least…

A: Given : Sample Size, n = 3084 confidence level,c=0.9 Significance level, α…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: A poll of 1060 adults in a country was conducted by telephone. Of those surveyed, 169 had…

A: The sample size is 1060 and number of success is 169.

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: In a study by Sallie Mae and Gallup, 223 of the 934 respondents said that they paid for their…

A: Obtain the 95% confidence interval for the proportion of students who paid for their education by…

Q: If n = 230 and X = 184, construct a 99% confidence interval for the population proportion, p.Give…

A: Given data n = 230 x = 184 sample proportion

Q: B. Edna ranked 75th in her senior class of 400 students. Rey is in the same senior class and has a…

A: We have to find whose rank is better in two problems B and C.

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: You are told that a survey produced a 90% confidence interval for the mean spent on utilities per…

A:

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: Phineas Phillips, from Philadelphia, has a fascination with fun phone facts. But Phineas has…

A:

Q: A national survey of 1000 adult citizens of a nation found that 19% dreaded Valentine's Day. The…

A:

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: If n = 330 and X = 264, construct a 95% confidence interval for the population proportion, p.

A: Ans#- From the provided information, Confidence level = 95% Sample size (n) = 330, x = 264 Sample…

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: In a sample of 310 adults, 177 had children. Construct a 87% confidence interval for the true…

A: Find z-critical value:…

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: Examining a random sample of records from my past Statistics classes, I found the 47 of the 282…

A:

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: If n = 440 and X = 352, construct a 90% confidence interval for the population proportion, p. Give…

A:

Q: Angela is trying to figure out the sample size for the data set she wants to collect. She is…

A: The larger the sample size, the less will be the value of standard error. Therefore, the range of…

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: psychologist wanted to know if students in her class were more likely to cheat if they were low…

A: ANSWER:After reviewing the data set, we need to determine whether the observed patterns support or…

Q: In a study, 110 children of a certain race in a certain city were randomly assigned to one of two…

A: There are two independent samples which are Preschool and No Preschool. We have to construct 95%…

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: Suppose you want to construct a 95% confidence interval for the difference

A:

Q: In one city, 27.8% of the 9000 students surveyed said they eat at the school cafeteria. Find the 95%…

A: To find the 95% confidence interval for the proportion of students who said they eat at the school…

Q: A researcher gathered a sample of participants who volunteered for a studying of phobias. She…

A: A researcher gathered a sample of participants who volunteered for a studying of phobias. She…