A manufacturing company packages shipments in either large or small boxes. A random sample of 40 shipmentsthat are packaged in large boxes is found to have a mean of 15 pounds and a standard deviation of 2.8 pounds. Aseparate random sample of 50 shipments that are packaged in small boxes is found to have a mean of 10 poundsand a standard deviation of 1.5 pounds. The manager would like to know if the data provide convincing evidencethat the true mean weight of all shipments that are packaged in small boxes is less than the true mean weight of allshipments that are packaged in large boxes. The manager tests Ho: Hs – = 0, Hạ: Hs – M < 0, where u = the truemean weight of all shipments that are packaged in large boxes and Us = the true mean weight of all shipments thatare packaged in small boxes. The conditions for inference have been met. What are the values of the test statisticand P-value for a t-test about a difference in means?Find the t-table here and the z-table here.O t=-10.19. The P-value is less than 0.0005.O z=-10.19. The P-value is less than 0.0002.O t= 10.19. The P-value is less than 0.0005.O z = 10.19. The P-value is less than 0.0002.

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Answered: A manufacturing company packages…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. What are the appropriate null and alternative hypotheses? Group of answer choices H 0: x̄ = 250 vs. H a: x̄ < 250 H 0: x̄ = 250 vs. H a: x̄ ≠ 250 H 0: x̄ = 250 vs. H a: x̄ > 250 H 0: μ = 250 vs. H a:μ < 250 H 0: μ = 250 vs. H a: μ ≠ 250 H 0: μ = 250 vs. H a: μ > 250

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