A manufacturer says that the standard deviation of the strength of wrapping cord is 9 pounds. A sample of 10 wrapping cords produces a variance of 121. At a = 0.05, test the claim that it is greater than 9 pounds.
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- Dr. Shoals predicts that people who walk a mile in moderately high heels will have less back pain than when they walk in very high heels. 27 participants walk in 4-inch heels and then 2.5-inch heels. He calculates the standard deviation of the difference scores and finds sD = 3.37. The mean back pain when walking in 4-inch heels is 6.75, and when walking in 2.5-inch heels, it is 3.25. What is the t statistic for this experimentAnn thinks that there is a difference in quality of life between rural and urban living. She collects information from obituaries in newspapers from urban and rural towns in Idaho to see if there is a difference in life expectancy. A sample of 3 people from rural towns give a life expectancy of xr¯=79��¯=79 years with a standard deviation of sr=7.57��=7.57 years. A sample of 14 people from larger towns give xu¯=82��¯=82 years and su=5.48��=5.48 years. Does this provide evidence that people living in rural Idaho communities have different life expectancy than those in more urban communities? Use a 5% level of significance. (a) State the null and alternative hypotheses: (Type ‘‘mu_r′′‘‘��_�″ for the symbol μr�� , e.g. mu_rnot=mu_u��_����=��_� for the means are not equal, mu_r>mu_u��_�>��_� for the rural mean is larger, mu_r<mu_u��_�<��_� , for the rural mean is smaller. )H0�0 = equation editor Equation Editor Ha�� = equation editor Equation Editor (b) The degree of…A medical researcher claims that the variance of the heart rates (in beats per minute) of smokers is greater than the variance of heart rates of people who do not smoke. Samples from two groups are selected and the data is given below. Using = 0.05, test whether there is enough evidence to support the claim. Smokers Non Smokers m = 25 n = 18 s = 36 s = 10
- It takes an average of 12.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 51 injured patients to immediately tell the truth about the injury and noticed that they averaged 14.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.48 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer V Hj: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly different from 12.8 at a =…The average weight of a group of students is 68 kg with a standard deviation of 8 kg. If the z-score of the weight of a student is 0.5, what is the weight of the student?A random sample of 10 subjects have weights with a standard deviation of 11.9848 kg . What is the variance of their weights ? Be sure to include the appropriate units with the result .
- It takes an average of 10.2 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 60 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.62 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and altemative hypotheses would be: Họ: Select an answer H1: ? Select an answer c. The test statistic (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is (? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that .. (Please show your answer to 4 decimal places.) O The data suggest the population mean is not significantly less than 10.2 at a = 0.01, so there is…The scores from the first exam of a pre-calculus class determined a mean of 73.5 and a standard deviation of 17.9. 1. Calculate an exam score that is 2 standard deviations below the mean. 2. Calculate an exam score that is 1 standard deviation above the mean.The time to smoke fish is normally distributed with an average of 5.3 hours and a standard deviation of 2.1 hours. What is the z score for a fish that take 10 hours to smoke?
- It has been reported that the variance of the speeds of drivers on the Turnpike near Somerset, PA is 64 for all vehicles. A driver who was pulled over near Somerset on the pike feels that value is incorrect and conducts a 4. survey of speeds. He finds that the standard deviation of 50 vehicles is 10.5 mph. At a 0.05, is the driver correct? %3DIt takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 70 injured patients to immediately tell the truth about the injury and noticed that they averaged 16.3 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.75 minutes. What can be concluded at the the α = 0.10 level of significance? a. For this study, we should use [Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H₁: ? Select an answer ✓ c. The test statistic ? = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? ✓ a f. Based on this, we should [Select an answer the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly greater than 14.5 at a = 0.10, so…In the 1800s, German physician Carl Reinhold, took millions of axillary (i.e. armpit) temperatures from soldiers. This study established that body temperature is normally distributed and the standard normal human body temperature is 98.6°F with a standard deviation of 0.72 °F. In a recent study, American researchers obtained 5,000 axillary temperatures from a Los Angeles hospital. The mean of these temperature readings was 97.9 F. Assuming a Type I error risk of no more than 5%, did the findings support the theory that human, body temperature has decreased since the 1800s? What is the Zcrit?