A manager is simulating the number of times a machine operator stops a machine to make adjustments. After careful study the manager found that the number of stops ranged from one to five per cycle and that each number of stops was equally likely. Using the random numbers 0.54 and 0.71 (in that order), determine how many stops for adjustments each of the next two cycles will have. The first cycle will have 4 3 stops and the second cycle will have stops
A manager is simulating the number of times a machine operator stops a machine to make adjustments. After careful study the manager found that the number of stops ranged from one to five per cycle and that each number of stops was equally likely. Using the random numbers 0.54 and 0.71 (in that order), determine how many stops for adjustments each of the next two cycles will have. The first cycle will have 4 3 stops and the second cycle will have stops
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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How do I get the 0.20 for probability in excel?

Transcribed Image Text:A manager is simulating the number of times a machine operator stops a machine to make adjustments. After careful study the
manager found that the number of stops ranged from one to five per cycle and that each number of stops was equally likely. Using the
random numbers 0.54 and 0.71 (in that order), determine how many stops for adjustments each of the next two cycles will have.
The first cycle will have
3 stops and the second cycle will have
Explanation
A random number of 0.54 falls within the range for a total number of stops of 3. A random number of 0.71 falls within the range for a total number of
stops of 4
stops
1
2
3
4
5
Probability
0.20
0.20
0.20
0.20
0.20
stops
Corresponding Random Numbers
0≤x≤0.20
0.20 < x≤ 0.40
0.40 < x≤ 0.60
0.60 < x≤ 0.80
0.80 x 1.00
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