A man is walking through a maze with 6 electric gates independent of each other. Let Ai = be the case that a door works.  P(A1) = 0.7  P(A2) = 0.4   P(A3 ) = 0.5  P(A4 ) =0.9   P(A5) = 0.3  P(A6)= 0.6 See picture for path.  B = (A1 U A4)    evaluate the probability of P(B)  C = (A5 ∩ A5 ) ∪ A3   Evaluate P(C)  Find the probabilty that he gets throught the maze.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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A man is walking through a maze with 6 electric gates independent of each other. Let Ai = be the case that a door works. 

P(A1) = 0.7  P(A2) = 0.4   P(A3 ) = 0.5  P(A4 ) =0.9   P(A5) = 0.3  P(A6)= 0.6

See picture for path. 

B = (AU A4)    evaluate the probability of P(B) 

C = (A5 ∩ A5 ) ∪ A3   Evaluate P(C) 

Find the probabilty that he gets throught the maze. 

 

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Step 1

The probability of an event gives the chances of occurrence of the event and its value lies between 0 and 1. The probability is computed by taking the ratio of number of favourable outcomes to total number of possible outcomes.

If two events are independent then the probability that both the events occur together is equal to multiplication of probability of both the events that is PAB=PA·PB. According to addition rule of probability the probability that at least one of the two events occur is given by PAB=PA+PB-PAB.

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