A loopful of bacteria containing 1000 bacterial cells is inoculated into a nutrient broth and incubated. After a negligible lag phase, the culture goes into exponential growth for two hours. The generation time for the bacterium is fifteen minutes. Which equation is the correct one to determine the number of cells present after two hours of log phase growth? Multiple Choice 1000 X 28 1000 X 16

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**Bacterial Cell Growth Calculation**

A loopful of bacteria containing 1000 bacterial cells is inoculated into a nutrient broth and incubated. After a negligible lag phase, the culture goes into exponential growth for two hours. The generation time for the bacterium is fifteen minutes. Which equation is the correct one to determine the number of cells present after two hours of log phase growth?

**Multiple Choice Options:**

- \( 1000 \times 2^8 \)
- \( 1000 \times 16 \)
- \( 1000 \times 2 \times 2 \times 15 \)
- \( 1000 \times 2^2 \)

**Explanation:**

To determine the number of bacterial cells after two hours, consider the following:

- **Initial Number of Cells:** 1000
- **Generation Time:** 15 minutes
- **Total Time of Growth:** 2 hours (120 minutes)

Calculate the number of generations that occur in 120 minutes:

\[ \text{Number of Generations} = \frac{120 \text{ minutes}}{15 \text{ minutes/generation}} = 8 \]

Thus, the number of cells after 8 generations can be calculated using the equation:

\[ \text{Final Number of Cells} = 1000 \times 2^8 \]

This represents the solution choice: \( 1000 \times 2^8 \)
Transcribed Image Text:**Bacterial Cell Growth Calculation** A loopful of bacteria containing 1000 bacterial cells is inoculated into a nutrient broth and incubated. After a negligible lag phase, the culture goes into exponential growth for two hours. The generation time for the bacterium is fifteen minutes. Which equation is the correct one to determine the number of cells present after two hours of log phase growth? **Multiple Choice Options:** - \( 1000 \times 2^8 \) - \( 1000 \times 16 \) - \( 1000 \times 2 \times 2 \times 15 \) - \( 1000 \times 2^2 \) **Explanation:** To determine the number of bacterial cells after two hours, consider the following: - **Initial Number of Cells:** 1000 - **Generation Time:** 15 minutes - **Total Time of Growth:** 2 hours (120 minutes) Calculate the number of generations that occur in 120 minutes: \[ \text{Number of Generations} = \frac{120 \text{ minutes}}{15 \text{ minutes/generation}} = 8 \] Thus, the number of cells after 8 generations can be calculated using the equation: \[ \text{Final Number of Cells} = 1000 \times 2^8 \] This represents the solution choice: \( 1000 \times 2^8 \)
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