A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m/s. (a) How long does it take for him to reach maximum height? tmax= (b) What is the maximum height? ymax= (c) How far does he jump? R= (d) Use Equation vž = vy – 2gAy to find the maximum height he reaches. ymax = %3D -
A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m/s. (a) How long does it take for him to reach maximum height? tmax= (b) What is the maximum height? ymax= (c) How far does he jump? R= (d) Use Equation vž = vy – 2gAy to find the maximum height he reaches. ymax = %3D -
College Physics
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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter3: Two-dimensional Kinematics
Section: Chapter Questions
Problem 28PE: (a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by...
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Q2-a
Q2:
A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at
a speed of 11 m/s.
(a) How long does it take for him to reach maximum height? tmax=
(b) What is the maximum height? ymax=
(c) How far does he jump? R=
(d) Use Equation v = vy – 2gAy to find the maximum height he reaches. ymax
إجابتك](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e76174a-38e0-4cf3-b643-1ab237406098%2F353b6566-199a-424e-bce3-79234822b641%2Fv72odgs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:نقطتان )2(
Q2-a
Q2:
A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at
a speed of 11 m/s.
(a) How long does it take for him to reach maximum height? tmax=
(b) What is the maximum height? ymax=
(c) How far does he jump? R=
(d) Use Equation v = vy – 2gAy to find the maximum height he reaches. ymax
إجابتك
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