A long aluminum cylinder with a diameter of 5 cm is initially at a temperature of 200oC and is suddenly exposed to 70oC convection and h = 525W /m2 oC Find the 1.25 cm diameter temperature and the heat loss per unit length 1 minute after the cylinder is subjected to convection. Thermal properties of the material k=215 W/moC a= 8,4x10-5m2/s ρ=2700kg/m3 CP=0.9kJ/kgoC
A long aluminum cylinder with a diameter of 5 cm is initially at a temperature of 200oC and is suddenly exposed to 70oC convection and h = 525W /m2 oC Find the 1.25 cm diameter temperature and the heat loss per unit length 1 minute after the cylinder is subjected to convection. Thermal properties of the material k=215 W/moC a= 8,4x10-5m2/s ρ=2700kg/m3 CP=0.9kJ/kgoC
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
A long aluminum cylinder with a diameter of 5 cm is initially at a temperature of 200oC and is suddenly exposed to 70oC convection and h = 525W /m2 oC
Find the 1.25 cm diameter temperature and the heat loss per unit length 1 minute after the cylinder is subjected to convection.
Thermal properties of the material
k=215 W/moC
a= 8,4x10-5m2/s
ρ=2700kg/m3
CP=0.9kJ/kgoC
![1.0
-100
50
\30
Heisler diagrams for cylinder
0.7
18
0.5
0.4
0.3
0.2
0.6
1.0
0.7
0.81.21.6
2.5 3.0
0.1
0.3
2
3
4
0.2
Bi = klhr,
0.1
100
0.07
90
0.05
80
0.04
0.03
0.02
0.01
0.007
0.005
0.004
0.003
0.002
30 35 40
0.001
2
3
4 6 8 10 12 14 16 18 20 22 24 26 28 30 40 50 60 70 80 90100 115 130 150200 300o
(atlr) = Fo](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd13fb86d-e34d-463b-bc8e-cc2ee9bf963d%2F3c079aae-ee22-48ac-8fba-b520d80988b9%2F17h3wll_processed.png&w=3840&q=75)
Transcribed Image Text:1.0
-100
50
\30
Heisler diagrams for cylinder
0.7
18
0.5
0.4
0.3
0.2
0.6
1.0
0.7
0.81.21.6
2.5 3.0
0.1
0.3
2
3
4
0.2
Bi = klhr,
0.1
100
0.07
90
0.05
80
0.04
0.03
0.02
0.01
0.007
0.005
0.004
0.003
0.002
30 35 40
0.001
2
3
4 6 8 10 12 14 16 18 20 22 24 26 28 30 40 50 60 70 80 90100 115 130 150200 300o
(atlr) = Fo
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