a list, C, of distinct elements, in increasing order, that are in A but not in B and in B but not in A.
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Let A and B be two integers valued arrays of sizes n1 & n2 respectively. The elements of the two arrays are sorted in increasing order and may contain duplicate elements.
It is required to form a list, C, of distinct elements, in increasing order, that are in A but not in B and in B but not in A. (There shall be no duplicate elements in list C.)
The two arrays, A & B, can only be traversed once.
Example:
A: -2, 2, 4, 4, 4, 7, 9, 9, 9, 12, 15,
B: 1, 2, 5, 9, 15, 15, 15, 17, 17, 17
C: -2, 1, 4, 5, 7, 12, 17
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- 25. Minimum Difference Sum Given an array of n integers, rearrange them so that the sum of the absolute differences of all adjacent elements is minimized. Then, compute the sum of those absolute differences. Example n = 5 arr = [1, 3, 3, 2, 4] If the list is rearranged as arr' = [1, 2, 3, 3, 4], the absolute differences are /1-2/ = 1, 12-3|= 1, 13- 3|=0, 13-4/= 1. The sum of those differences is 1+1+0+1 = 3. Function Description Complete the function minDiff in the editor below. minDiff has the following parameter: arr: an integer array Returns: int: the sum of the absolute differences of adjacent elements Constraints 1 > #include ... 'PRENENANG 19 20 21 22 23 24 25 26 28 * Complete the 'minDiff' function below. ★ 27 int minDiff(int arr_count, int* arr) { * The function is expected to return an INTEGER. * The function accepts INTEGER_ARRAY arr as parameter. */ 29 } 30 31 > int main() ...[] [] partite_sets In the cell below, you are to write a function "partite_sets (graph)" that takes in a BIPARTITE graph as its input, and then returns a single list whose two entries are the partite sets of the graph as lists (the order of the sets outputed does not matter). After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (partite_sets({"A" : ["B", "C"], "B" : partite_sets({"A" : ["B", "C"], "B" : ["A"], "C" : ["A"]}), ["A", "D"], "C" : ["A", "D"], "D" : ["B", "C"]})) This should return [["B","C"], ["A"]] [["A","D"], ["B","C"]] (the order in which the entries appear does not matter) Python PythonTROUBLESHOOT my PYTHON code, please :) The code of a sequential search function is shown on textbook page 60. In fact, if the list is already sorted, the search can halt when the target is less than a given element in the list. For example, given my_list = [2, 5, 7, 9, 14, 27], if the search target is 6, the search can halt when it reaches 7 because it is impossible for 6 to exist after 7. Define a function linearSearchSorted, which is used to search a sorted list. This function displays the position of the target item if found, or 'Target not found' otherwise. It also displays the elements it has visited. To test your function, search for these targets in the list [2, 5, 7, 9, 14, 27]: 2, 6, 14, 27 and 28. Expected output: List: [2, 5, 7, 9, 14, 27] Search target: 2 Elements visited: 2 Target found at position 0 Search target: 6 Elements visited: 2 5 7 Target not found Search target: 14 Elements visited: 2 5 7 9 14 Target found at position 4 Search target: 27 Elements visited: 2…
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- Exercise B: "Matrix Addition" For this exercise you will design and implement a function that takes two matrix arguments and computes their sum (if and only if a sum can actually be computed, returning an empty list otherwise). Two matrices can only be added together if they have exactly the same dimensions. If the dimensions are acceptable, then the matrix sum will have the same dimensions as either of the operands, and the value of each element in the matrix sum is itself the sum of the corresponding elements in the operand matrices. And although it does makes sense to test rectangularity before attempting addition, you need not perform this step (since you did it above). In order to complete this task, you will need to: ensure you know how matrix addition can be performed² ● Your submission for this exercise:6.Code for- an array of meeting time intervals consisting ofstart and end times [[s1,e1],[s2,e2],...] (si < ei),determine if a person could attend all meetings. For example,Given [[0, 30],[5, 10],[15, 20]],return false.""".There are many differences between array and linked list, one of these differences: a. In a linked list insertion and deletion takes more time b. Array supports random access while linked List supports sequential access c. in linked list, elements are stored in contiguous memory location while in array are stored anywhere in the memory d. None of the above
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