Following is the partition function for quicksort, where we have used the leftmost number as a pivot. Assume that our array, ARR = {14, 8, 7, 38, 22, 15, 9}, which is 7 in size. What will be the array ARR after we apply "partition(A, 0, 6)"* 9, 15, 22, 38, 7, 8, 14 7, 8, 9, 14, 15, 22, 38 9, 8, 14, 7, 22, 15, 38 9, 8, 7, 14, 22, 15, 38 7, 9, 15, 22, 38, 14, 6 38, 22, 15, 14, 9, 8, 7
Following is the partition function for quicksort, where we have used the leftmost number as a pivot. Assume that our array, ARR = {14, 8, 7, 38, 22, 15, 9}, which is 7 in size. What will be the array ARR after we apply "partition(A, 0, 6)"* 9, 15, 22, 38, 7, 8, 14 7, 8, 9, 14, 15, 22, 38 9, 8, 14, 7, 22, 15, 38 9, 8, 7, 14, 22, 15, 38 7, 9, 15, 22, 38, 14, 6 38, 22, 15, 14, 9, 8, 7
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Following is the partition function for quicksort, where we have used the leftmost number as a pivot. Assume that our array, ARR = {14, 8, 7, 38, 22, 15, 9}, which is 7 in size. What will be the array ARR after we apply "partition(A, 0, 6)"*
9, 15, 22, 38, 7, 8, 14
7, 8, 9, 14, 15, 22, 38
9, 8, 14, 7, 22, 15, 38
9, 8, 7, 14, 22, 15, 38
7, 9, 15, 22, 38, 14, 6
38, 22, 15, 14, 9, 8, 7
![int partition(int A[], int left, int right){
int pivot = A[left];
int start = left;
int end = right;
while(start<end){
while(A[start]<=pivot){
start++;
}
while(A[end]>pivot){
end --;
}
if(start<end){
swap(A[start], A[end]);
}
}
swap (A[left], A[end]);
return end;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6887688b-70f6-4104-af60-6900f6a7be74%2F86d39a6d-ee20-4203-bb3c-bb0968dc478c%2F9g8oyj_processed.png&w=3840&q=75)
Transcribed Image Text:int partition(int A[], int left, int right){
int pivot = A[left];
int start = left;
int end = right;
while(start<end){
while(A[start]<=pivot){
start++;
}
while(A[end]>pivot){
end --;
}
if(start<end){
swap(A[start], A[end]);
}
}
swap (A[left], A[end]);
return end;
}
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