A line is laid out using a 50-m tape. The standard error of each tape length laid out is assumed to be ±0.03. If a total length of 2400 m is laid out, what is the standard error of the length of the line? A. ±0.028 C. ±1.440 B. ±0.009 D. ±0.208 Determine the correct length of a line, 256.32 m long, measured using a 50 m steel tape at 38 °C. The steel tape was calibrated at 20 °C. A 256.310 C. 256.374 B. 256.266 D. 256.330 ps.

Solution in this format:Given:Required:Solution: The measured values of distance AB were recorded. Compute the following: round up the values in three decimal placesa. Probable error b. Standard deviationc. Standard error Trials Distance 1 200.672 2 200.676 3 200.522 4 200.699 5 200.501

a. find the distance from A to B b. find bearing from A to B

A 50m tape was used to measure a line DE. The adjusted distance of line DE is  120.23m long. If the tape is 0.04 too short, what is the measure distance?

A polygon has the following data as given in the table. Determine the adjusted measurement of its interior angles. Round-off answers to degrees-minutes. Interior Angle Ꮎ° 12345 117 98 87 150 102 Weighted Measurement 3 4 157 5 2

How to solve for the Taped Distance and Percentage of Error? Show your step-by-step solution.

42. A 30-m steel tape is used to measure the distance of a line. The measured distance is 457.65 m. After the tape was calibrated, it was found that it is 16 mm too short. What is the correct length of the line? +8 8 A. 457.406 m C. 457.921 m D. 457.125 m B. 457.894 m

(engineering mechanics) solutions if possible

The following values are determined after measuring a line thru series of tape measurements are were recorded to be: 750.37, 750.43, 750.41, 750.50, 750.42 and 750.39. What is the probable error of any single measurement to the nearest hundredths? Choices: +-0.03   +-0.02   +-0.01   +-0.04

2. During the measurement at the sides of the slope, the data was recorded into three bays, the following information (Table 1.0) was obtained: Table 1.0 Difference in Tension (N) Temperature (°C) Bay Measured Length (m) level between end (m) 1 25.842 19 +0.285 150 27.365 18 -0.236 120 3 21.645 21 -0.239 160 The 30 meter tape used has a mass of 0.400 N/m and a cross-sectional area of 3.00 mm?. It was standardised on the flat at 20 °C under a pull of 100 N, the actual length was 29.995 m during the measuring works. The coefficient of linear expension for the materials of the tape us 0.000015 / °C and Young's Modulus is 20.5 x 104 MN/m?. Calculate the absolute length of survey line in 3 decimal point. Slope correction = -v² 2s Sagging correction = - w²L³ 24P? Tension correction = (P – Ps) EL AE Temperature correction = a (T-Ts) (L)