A light ray passes through substances 1, 2, and 3, as shown. The indices of refraction for these three substances are n1, n2, and n3, respectively. Ray segments in 1 and 3 are parallel. 01 1 2 n2 3 02 n3 O One can conclude that 1. n2 must be less than n3. 2. nį must be equal to 1.00. 3. nz must be the same as nį. 4. n2 must be less than n1. 5. all three indices must be the same.

A light ray passes through substances 1, 2, and 3, as shown. The indices of refraction for these three substances are n1, n2, and n3, respectively. Ray segments in 1 and 3 are parallel. 01 1 2 n2 3 02 n3 O One can conclude that 1. n2 must be less than n3. 2. nį must be equal to 1.00. 3. nz must be the same as nį. 4. n2 must be less than n1. 5. all three indices must be the same.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 96PQ

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Concept explainers

Dispersion of White Light

Snell’s law is a formula that gives a relation between the angle of incidence and angle of refraction and is given as:

Question

Please explain why it would be that answer, thank youuuuu!

A light ray passes through substances 1, 2,
and 3, as shown.
The indices of refraction for these three
substances are n1, n2, and n3, respectively.
Ray segments in 1 and 3 are parallel.
1
n1
2
n2
3
02
n3
One can conclude that
1. n2 must be less than n3.
2. nį must be equal to 1.00.
3. nz must be the same as nį.
must be less than n1.
4. n2
5. all three indices must be the same.

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