A light ray incident at 45 degrees passes through two dielectric materials with the indices of refraction and thicknesses given. If the ray strikes the surface of the first dielectric at a height of 2 cm, at what height will it strike the screen. T 2cm n = 1 n=1.5 n=1.3 45° 3cm 4cm n=1 5cm Screen

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### Light Refraction Through Dielectric Materials

**Problem Statement:**

A light ray incident at 45 degrees passes through two dielectric materials with the indices of refraction and thicknesses given. If the ray strikes the surface of the first dielectric at a height of 2 cm, at what height will it strike the screen?

**Diagram Explanation:**

The diagram illustrates a light ray passing through materials with different refractive indices.

- **Region 1 (Air):** 
  - Refractive Index: \( n = 1 \) 
  - The light ray enters at a 45-degree angle to the surface.

- **Region 2 (First Dielectric):**
  - Refractive Index: \( n = 1.5 \)
  - Width: 3 cm 
  - The ray path bends due to the change in refractive index.

- **Region 3 (Second Dielectric):**
  - Refractive Index: \( n = 1.3 \)
  - Width: 4 cm 
  - Further bending occurs.

- **Region 4 (Air):**
  - Refractive Index: \( n = 1 \)
  - Width: 5 cm 
  - The light exits the dielectrics and continues to the screen.

**Screen:**
- The final surface where the ray intersects after passing through both dielectric layers.

### Key Query:
Determine the vertical height at which the light ray will strike the screen, factoring in the changes in direction due to refraction at each interface. 

To solve this, apply Snell's Law at each interface and use geometric principles to trace the path of the refracted ray.
Transcribed Image Text:### Light Refraction Through Dielectric Materials **Problem Statement:** A light ray incident at 45 degrees passes through two dielectric materials with the indices of refraction and thicknesses given. If the ray strikes the surface of the first dielectric at a height of 2 cm, at what height will it strike the screen? **Diagram Explanation:** The diagram illustrates a light ray passing through materials with different refractive indices. - **Region 1 (Air):** - Refractive Index: \( n = 1 \) - The light ray enters at a 45-degree angle to the surface. - **Region 2 (First Dielectric):** - Refractive Index: \( n = 1.5 \) - Width: 3 cm - The ray path bends due to the change in refractive index. - **Region 3 (Second Dielectric):** - Refractive Index: \( n = 1.3 \) - Width: 4 cm - Further bending occurs. - **Region 4 (Air):** - Refractive Index: \( n = 1 \) - Width: 5 cm - The light exits the dielectrics and continues to the screen. **Screen:** - The final surface where the ray intersects after passing through both dielectric layers. ### Key Query: Determine the vertical height at which the light ray will strike the screen, factoring in the changes in direction due to refraction at each interface. To solve this, apply Snell's Law at each interface and use geometric principles to trace the path of the refracted ray.
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