A light of wavelength A = 600 nm is illuminated on a double-slit and a pattern is observed on a screenthat is at 2.0 m away from the slits. The central diffraction maximum of the pattern has a width of 4.0cm (from M = -1 to M = +1) and the fourth interference bright fringes (m = +4) are missing on both%3Dsides of the central line.a Find-the-width of each-slit.Find the separationbetween the two slits.c Find the path-Hength-difference_for the point on the screen where-you see the third orderinterference bright fringe.d) If a light with wavelength A = 400 nm is used on the same double slit, find how many bright fringes%3Dappear inside the central diffraction maximum. Must explain or show your work.

Given:wavelength of light, λ = 600 nm = 600×10-9 m = 6×10-7 mdistance between the slit and screen, D…

A light of wavelength d = 600 nm is illuminated on a double-slit and a pattern is observed on a screen that is at 2.0 m away from the slits. The central diffraction maximum of the pattern has a width of 4.0 cm (from M = -1 to M = +1) and the fourth interference bright fringes (m = +4) are missing on both %3D %3D

A light of wavelength d = 600 nm is illuminated on a double-slit and a pattern is observed on a screen that is at 2.0 m away from the slits. The central diffraction maximum of the pattern has a width of 4.0 cm (from M = -1 to M = +1) and the fourth interference bright fringes (m = +4) are missing on both %3D %3D