A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 8.50 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram
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Solve using GUESS method. Geometric Optics
3. A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 8.50 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram.
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- 1) A 12.0 cm tall object is placed to the left of a lens of unknown focal length. The lens creates an image to the right of the lens, as shown in the picture. Object a b) Image s Using a straightedge, locate the focal points of the lens. Mark these focal points with dots on the picture. Is this image real or virtual? Explain briefly. The magnification of the image is -0.75, and the object distance is 15.0 cm. Find both the image location d; and the focal length of the lens f.1) What is f, the focal length of the mirror? If the mirror is concave f is positive. If the mirror is convex, f is negative. 2) What is y₂, the y-coordinate of the image of the tip of the arrow? 3) The object arrow is now moved such that image distance doubles, i.e., Ximage, new = -177 cm. What is Yimage, new, the new y-coordinate of the image of the tip of the arrow? cm Submit 000 4) The object arrow is now moved to x = x1,new = -29 cm. What is arrow? (a) cm Submit (b) 5) Which of the rays in the diagram is not reflected as shown? (c) Submit cm Submit cm Submit Y2, new' (a)+ (b) (c) the new y-coordinate of the image of the + +A small insect is placed 5.40 cm from a 6.00-cm-focal-length lens. a) Calculate the position of the image. Follow the sign conventions. Express your answer using two significant figures and include the appropriate units. b) Calculate the angular magnification. Express your answer using two significant figures.
- A converging lens with a focal length of 12 cm forms a real image of 7.40 mm tall and 18.000 cm to the right of the lens. (a) Determine the position and size of the object. ст mm Is the image upright or inverted? A. Upright B. Inverted Are the object and image on the same size or opposite sides of the lens? You should draw the ray-diagram for this situation. A. same B. oppsiteA lens forms an image of an object. The object is 15.4 cm from the lens. The image is 11.7 cm from the lens on the same side as the object. a. What is the absolute value of the focal lens of the lens? cm b. Is the lens converging or diverging? converging diverging c. If the object is 8.48 mm tall, how tall is the image? mm d. Is the image upright or inverted? upright O inverted e. To receive full credit for this problem you will need to draw a principal ray diagram, including three principal rays. yes, got it - I will attach the diagram in Canvas with the rest of my work. no, I don't have a diagram to attach.Question 2 You go for a free eye test in City Pharmacy. (a) The prescription given to you for eyeglasses reads: “P = +2.0D”. Explain what this means in terms of the focal length, and the type of lens needed.(b) From this prescription, does this mean you are Nearsighted or Farsighted?
- In the following three scenarios, an object is located on one side of a converging lens. In each case, you must determine if the lens forms an image of this object. If it does, you also must determine the following. whether the image is real or virtual whether the image is upright or inverted the image's location, q the image's magnification, M The focal length is f = 60.0 cm for this lens. Set both q and M to zero if no image exists. Note: If q appears to be infinite, the image does not exist (but nevertheless set q to 0 when entering your answers to that particular scenario). (a) The object lies at position 60.0 cm. (Enter the value for q in cm.) q= cmM= Select all that apply to part (a). realvirtualuprightinvertedno image (b) The object lies at position 7.06 cm. (Enter the value for q in cm.) q= cmM= Select all that apply to part (b). realvirtualuprightinvertedno image (c) The object lies at position 300 cm. (Enter the value for q in cm.) q= cmM= Select all that…The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.781 m, d2 = 0.604 m, and h = 7.50E-2 m. What is the image height (in m; answer sign and magnitude)?Which of the following statements for single optic devices are true? Choose all that apply. a. Any physicist worth their weight in garbanzo beans (not chick peas) knows that concave lenses will have a positive focal length. b. For virtual images, the image distance is positive and the object distance is negative. c. By convention, if the image height is positive then the image is upright. d. If an optic produces an image with a magnification of 0.6, then the image is diminished. e. Experiments have shown that convex mirrors can create real images. f. If an image has a magnification of -6, then the image is real.