A laser beam of intensity 1.03 x 103 W/m² with a wavelength of 576 nm is incident on an opaque screen with a tiny circular aperture of radius 1.01 x 107 m. Apply the Huygens-Fresnel principle to find the intensity of the diffracted light at a distance of 1.03 cm from the center of the aperture. 1.03e-08 W/m^2 X
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- The intensity 1 of light at a depth of x meters below the surface of a lake satisfies the differential equation d l/dx = (-1.4) 1. (a) At what depth is the intensity half the intensity lo at the surface. 0.495m 0.258m 0.654m 0.754mRefractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of the glass is 1.5 ? Snell's Law: n; (sin I) = n, (sin R) So, Sin R = n; (sin I) / n And, R = arcsin (n; (sin I) / n,) For each angle I, find angle R: 5. I=0, R = 6. I=45, R = 7. I= 60, R = 8. I = 75, R = = arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees Wavelength in Air- Light- Angle of Light -Wavelength in Glass Normal 90° R Air nj-1 GlassThe refractive index of a material is 1.33. If velocity of light in vacuum is 3 x 10 ms-, find the velocity of light in the material.
- A laser beam with a total power of 22 watts is incident at a normal angle of incidence on a Lambertian surface. How much power reaches a detector with an area of 0.1 cm2 at an angle of 25 degrees located at a distance of 40 cm from where the beam strikes the surface? Please check closest answer. 0.525 mW 0.397 mW 0.247 mW 0.421 mWA solar cooker has a rectangular light collection area of 80 cm X 125 cm. If sunlight of intensity 1.2 kW/m² is incident on its surface at an angle of 60 degrees with respect to the normal, calculate the power collected by the solar cooker. O 0.4 kW 0 1 kW O 1.2 kW O 0.6 kWWhat is the refractive index of the material in which the speed of light is 1.28×108 m/s. (c = 3.0 × 108 m/s) O 1.12 O 1.20 1.80 1.65 O 2.34
- How many centimetres is the light ray displaced after passing through the 5.50 cm thick sheet of material (n = 1.30) with an incident angle of θ = 34.0 °?Problem 13: A ray of light is incident on an air/water interface. The ray makes an angle of 01 = 22 degrees with respect to the normal of the surface. The index of the air is n = 1 while water is n₂ = 1.33. Part (b) Numerically, what is the angle in degrees? 0₂=1 Part (a) Choose an expression for the angle (relative to the normal to the surface) for the ray in the water, 02. Answer Saved Successfully! 8₂=asin (sin()) sin() cos() cotan() asin() atan() acotan() cosh() sinh() tanh() cotanh() Degrees O Radians Submit tan() acos() E 4 5 6 1 2 3 () Hint * Feedback 7 8 9 HOME 1 + 0 VO BACKSPACE DEL CLEAR - I give up! . ni END n2 0₁ 02₂A light ray in glass (refractive index 1.57) arrives at the glass-water interface at an angle of 0 = 48° with the normal. The index of refraction of water is 1.33. What is the angle of refraction @ that a refracted ray makes with the normal ? water glass O 42° O 56° O 61° O 20°