Refractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of the glass is 1.5 ? Snell's Law: n; (sin I) = n₂ (sin R) So, Sin R=n; (sin I) / n And, R = arcsin (n; (sin I) / n,) For each angle I, find angle R: 5. I=0, R = 6. I45. R= = arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees
Refractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of the glass is 1.5 ? Snell's Law: n; (sin I) = n₂ (sin R) So, Sin R=n; (sin I) / n And, R = arcsin (n; (sin I) / n,) For each angle I, find angle R: 5. I=0, R = 6. I45. R= = arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees
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Chapter1: The Nature Of Light
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![Refractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials
such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and
angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of
the glass is 1.5 ?
Snell's Law: n; (sin I) = n, (sin R)
So, Sin R = n; (sin I) / n
And, R = arcsin (n; (sin I) / n,)
For each angle I, find angle R:
5. I=0, R =
6. I=45, R =
7. I= 60, R =
8. I = 75, R =
=
arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees
Wavelength in Air-
Light-
Angle
of Light
-Wavelength in Glass
Normal
90°
R
Air
nj-1
Glass](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa738f338-4b97-4795-af96-9c8545b72d67%2Fd4d9ab39-59a6-4d28-9250-cbf9f7771042%2F0n6dju_processed.png&w=3840&q=75)
Transcribed Image Text:Refractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials
such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and
angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of
the glass is 1.5 ?
Snell's Law: n; (sin I) = n, (sin R)
So, Sin R = n; (sin I) / n
And, R = arcsin (n; (sin I) / n,)
For each angle I, find angle R:
5. I=0, R =
6. I=45, R =
7. I= 60, R =
8. I = 75, R =
=
arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees
Wavelength in Air-
Light-
Angle
of Light
-Wavelength in Glass
Normal
90°
R
Air
nj-1
Glass
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