A laser beam moving at velocity c relative to us is turned on just as three (hypothetical) observers pass by us in the same direction as the beam. Observer 1 has velocity c/2, observer 2 has velocity 0.999c, and observer 3 has velocity c. If metersticks had different lengths in different frames, or clocks ticked at different rates in different frames, it is not impossible that the first and second observers could measure the beam to be moving at speed c relative to them, but the third observer could not find that the beam is moving at speed c relative to her. Prove this quantitavely.

icon
Related questions
Question

A laser beam moving at velocity c relative to us is turned on just as three (hypothetical) observers pass by us in the same direction as the beam. Observer 1 has velocity c/2, observer 2 has velocity 0.999c, and observer 3 has velocity c.

If metersticks had different lengths in different frames, or clocks ticked at different rates in different frames, it is not impossible that the first and second observers could measure the beam to be moving at speed c relative to them, but the third observer could not find that the beam is moving at speed c relative to her. Prove this quantitavely.

0₁-
c/2
0₂
0.999c
03-
C
Transcribed Image Text:0₁- c/2 0₂ 0.999c 03- C
Expert Solution
Step 1

We will first write the expression, which relates the velocities of a particle, as observed in two frames. We use this expression to study the given situations. The details are as below.

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS