A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 4.80 m from the slits. If the bright interference fringes on the screen are separated by 1.56 cm, what is the wavelength of the laser light? nm

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 4.80 m from the slits. If the bright interference fringes on the screen are separated by 1.56 cm, what is the wavelength of the laser light?

**Answer Box:**
\[ \text{nm} \]

---

**Explanation:**

This problem is about the interference pattern produced in a double-slit experiment. The separation of the slits, the distance from the slits to the screen, and the separation of the interference fringes are given. You must calculate the wavelength of the laser light, usually using the formula for fringe separation in a double-slit experiment:

\[
\lambda = \frac{xd}{L}
\]

where:
- \(\lambda\) = wavelength of the laser light,
- \(x\) = separation of the fringes on the screen (1.56 cm converted to meters),
- \(d\) = separation of the slits (0.195 mm converted to meters),
- \(L\) = distance from the slits to the screen (4.80 m).

To solve, substitute the given values into the equation and calculate \(\lambda\) in meters, then convert to nanometers.
Transcribed Image Text:**Problem Statement:** A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 4.80 m from the slits. If the bright interference fringes on the screen are separated by 1.56 cm, what is the wavelength of the laser light? **Answer Box:** \[ \text{nm} \] --- **Explanation:** This problem is about the interference pattern produced in a double-slit experiment. The separation of the slits, the distance from the slits to the screen, and the separation of the interference fringes are given. You must calculate the wavelength of the laser light, usually using the formula for fringe separation in a double-slit experiment: \[ \lambda = \frac{xd}{L} \] where: - \(\lambda\) = wavelength of the laser light, - \(x\) = separation of the fringes on the screen (1.56 cm converted to meters), - \(d\) = separation of the slits (0.195 mm converted to meters), - \(L\) = distance from the slits to the screen (4.80 m). To solve, substitute the given values into the equation and calculate \(\lambda\) in meters, then convert to nanometers.
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