A large stationary Brayton-cycle gas turbine power plant delivers a Net Power Output of 100 MW (Wnet) to an electric generator. The minimum temperature in the cycle is 300 K, and the maximum temperature is 1600 K. The minimum pressure in the cycle is 100 kPa, and the compressor pressure ratio is 14 to 1. Assume that the compressor has an isentropic efficiency of 85% and the turbine an isentropic efficiency of 88%. b. c. Turbine Output WT (MW) | d. Back Work Ratio (%) e. Thermal Efficiency (%) Properties of air: k = 1.4 Cp = 1.01 kJ/kg-K Cv=0.718 kJ/kg-KR = 0.2871 kJ/kg-K

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question

SIMPLE NON-IDEAL BRAYTON CYCLE GAS TURBINE: Use Cold-Air Standard Analysis

Show complete solution and explain briefly.

A large stationary Brayton-cycle gas turbine power plant delivers a Net Power Output of 100 MW (Wnet) to
an electric generator. The minimum temperature in the cycle is 300 K, and the maximum temperature is
1600 K. The minimum pressure in the cycle is 100 kPa, and the compressor pressure ratio is 14 to 1.
Assume that the compressor has an isentropic efficiency of 85% and the turbine an isentropic efficiency of
88%.
c. Turbine Output WT (MW)
d. Back Work Ratio (%)
e. Thermal Efficiency (%)
Properties of air:
k = 1.4
Cp=1
Cv=0.718 kJ/kg-KR = 0.2871 kJ/kg-K
= 1.01 kJ/kg-K
Transcribed Image Text:A large stationary Brayton-cycle gas turbine power plant delivers a Net Power Output of 100 MW (Wnet) to an electric generator. The minimum temperature in the cycle is 300 K, and the maximum temperature is 1600 K. The minimum pressure in the cycle is 100 kPa, and the compressor pressure ratio is 14 to 1. Assume that the compressor has an isentropic efficiency of 85% and the turbine an isentropic efficiency of 88%. c. Turbine Output WT (MW) d. Back Work Ratio (%) e. Thermal Efficiency (%) Properties of air: k = 1.4 Cp=1 Cv=0.718 kJ/kg-KR = 0.2871 kJ/kg-K = 1.01 kJ/kg-K
Expert Solution
steps

Step by step

Solved in 4 steps with 20 images

Blurred answer
Knowledge Booster
Power Plant Engineering
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY