A large plate of aluminum 5.0 cm thick and initially at 200°C js suddenly exposed to the convection environment of Example 4-5. Calculate the temmperature at adepth of 1.25 cm/irom one of the faces 1 min after the plate has been exposed to the environment. How much energy has been removed per unit area from the plate in this time? 2L-5cm L = 2.5cm - Ti's 200c 군- Imin = (*60 L=2.5cm %3D %3D - 60 S Note: (x) is measured from center (a)
A large plate of aluminum 5.0 cm thick and initially at 200°C js suddenly exposed to the convection environment of Example 4-5. Calculate the temmperature at adepth of 1.25 cm/irom one of the faces 1 min after the plate has been exposed to the environment. How much energy has been removed per unit area from the plate in this time? 2L-5cm L = 2.5cm - Ti's 200c 군- Imin = (*60 L=2.5cm %3D %3D - 60 S Note: (x) is measured from center (a)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A large plate of aluminum 5.0 cm thick and initially at 200°C is suddenly exposed to the convection
environment of Example 4-5. Calculate the temperature at adepth of 1.25 cm/rom one of the faces
1 min after the plate has been exposed to the environment. How much energy has been removed
per unit area from the plate in this time?
2L-5cm
L = 2.5cm
ot = I min =I *60
= 60 S
Ti's 200c
L=25cm
%3D
%3D
Note: (x) is measured from center
bin
T = centerline temperanure
(a)
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