A large container of benzene is transported on the truck. Determine (1) the level in each of the vent tubes A and B if the truck acceleration at a = 0.5 m/s². (2) the maximum constant acceleration of the truck without spill benzene from the vent tubes. When the truck is at rest, ha = hB = 0.1 m.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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A large container of benzene is transported on the truck. Determine (1) the level in each of the
vent tubes A and B if the truck acceleration at a = 0.5 m/s². (2) the maximum constant
acceleration of the truck without spill benzene from the vent tubes.
When the truck is at rest, ha = hg = 0.1 m.
-0.2 m
-2.0 m
0.2 m→
|A [0.25 m B
hAT
The
a
ent learning. Disser.
ie work and is not permitted.
ó copyrig.
- (including on the World v
SOLUTION
1.0 m
1.0 m
Δη
h'B
hg =0.1 m
hA = 0.1 m
h'a
Imaginary free surface
(a)
The imaginary surface of the benzene in the accelerated tank is shown above.
ac
tan0 =
(1)
0.5 m/s²
9.81 m/s²
0 = 2.91774938°
Ah = 1m * tan0 = 0.051m
3
Homework #2 Problems
h, = ha – Ah = 0.1 m – 0.051 m = 0.049m
hg = hg – Ah = 0.1 m + 0.051 m = 0. 151m
(2) The imaginary surface of the benzene in the accelerated tank will spill from vent B. Thus,
0.15m
ac
Ah = h'3 – hB = 0.25 m – 0.1 m = 0.15 m
tan0 =
1m
g
(0.15m
= 1.47 m/s²
ac = 9.81 m/s²
1m
instructors in.
Transcribed Image Text:A large container of benzene is transported on the truck. Determine (1) the level in each of the vent tubes A and B if the truck acceleration at a = 0.5 m/s². (2) the maximum constant acceleration of the truck without spill benzene from the vent tubes. When the truck is at rest, ha = hg = 0.1 m. -0.2 m -2.0 m 0.2 m→ |A [0.25 m B hAT The a ent learning. Disser. ie work and is not permitted. ó copyrig. - (including on the World v SOLUTION 1.0 m 1.0 m Δη h'B hg =0.1 m hA = 0.1 m h'a Imaginary free surface (a) The imaginary surface of the benzene in the accelerated tank is shown above. ac tan0 = (1) 0.5 m/s² 9.81 m/s² 0 = 2.91774938° Ah = 1m * tan0 = 0.051m 3 Homework #2 Problems h, = ha – Ah = 0.1 m – 0.051 m = 0.049m hg = hg – Ah = 0.1 m + 0.051 m = 0. 151m (2) The imaginary surface of the benzene in the accelerated tank will spill from vent B. Thus, 0.15m ac Ah = h'3 – hB = 0.25 m – 0.1 m = 0.15 m tan0 = 1m g (0.15m = 1.47 m/s² ac = 9.81 m/s² 1m instructors in.
A large container of benzene is transported on the truck. Determine (1) the level in each of the
vent tubes A and B if the truck acceleration at a = 1.5 m/s². (2) the maximum constant
acceleration of the truck without spill benzene from the vent tubes.
When the truck is at rest, ha = hg = 0.6 m.
0.2 m
→ -
-0.2 m
4.0 m
В
|A
ha
Ths
1 m
a
Transcribed Image Text:A large container of benzene is transported on the truck. Determine (1) the level in each of the vent tubes A and B if the truck acceleration at a = 1.5 m/s². (2) the maximum constant acceleration of the truck without spill benzene from the vent tubes. When the truck is at rest, ha = hg = 0.6 m. 0.2 m → - -0.2 m 4.0 m В |A ha Ths 1 m a
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