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Given the velocity through the exhaust of the rocket is: Umax (1-7) ¹/7 U(r) = Umax (1 Umax is a constant r is the radial coordinate out from the center of the engine R is the outside radius of exhaust flow Determine the reaction force of the exhaust in terms of: o II and R

Given the velocity through the exhaust of the rocket is: Umax (1-7) ¹/7 U(r) = Umax (1 Umax is a constant r is the radial coordinate out from the center of the engine R is the outside radius of exhaust flow Determine the reaction force of the exhaust in terms of: o II and R

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Given the velocity through the exhaust of the rocket is: \[ U(r) = U_{\text{max}} \left(1 - \frac{r}{R}\right)^{1/7} \] Where: - \( U_{\text{max}} \) is a constant. - \( r \) is the radial coordinate out from the center of the engine. - \( R \) is the outside radius of exhaust flow. Determine the reaction force of the exhaust in terms of: \( \rho, U_{\text{max}}, \) and \( R \).
Transcribed Image Text:Given the velocity through the exhaust of the rocket is: \[ U(r) = U_{\text{max}} \left(1 - \frac{r}{R}\right)^{1/7} \] Where: - \( U_{\text{max}} \) is a constant. - \( r \) is the radial coordinate out from the center of the engine. - \( R \) is the outside radius of exhaust flow. Determine the reaction force of the exhaust in terms of: \( \rho, U_{\text{max}}, \) and \( R \).
Expert Solution
Step 1: Given

The velocity through exhaust of the rocket is u left parenthesis r right parenthesis equals U subscript m a x end subscript open parentheses 1 minus r over R close parentheses to the power of 1 divided by 7 end exponent

U subscript m a x end subscript is constant.

R is the outside radius of exhaustr flow.

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