A large block is being pushed against a smaller block such that the smaller block remains elevated while being pushed. The mass of the smaller block is m = 0.65 kg. It is found through repeated experimentation that the blocks need to have a minimum acceleration of a = 12 m/s² in order for the smaller block to remain elevated and not slide down. What is the coefficient of static friction µg between the two blocks? Hs = 1.22 m 15↑

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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Description:
A large block is being pushed against a smaller block such that the smaller block remains elevated while being pushed. The mass of the smaller block is \( m = 0.65 \, \text{kg} \). It is found through repeated experimentation that the blocks need to have a minimum acceleration of \( a = 12 \, \text{m/s}^2 \) in order for the smaller block to remain elevated and not slide down. What is the coefficient of static friction \( \mu_s \) between the two blocks?

#### Calculation:
A user attempted to calculate the coefficient of static friction and entered:

\[
\mu_s = 1.22
\]

This answer was marked as Incorrect.

### Diagram Explanation:
The diagram on the right shows:
- A horizontal surface.
- A large block is shown in green with a smaller block on top of it to the right, labeled with mass \( m \).
- An arrow labeled \( \vec{a} \) points to the right, indicating the direction of acceleration.

This setup demonstrates that the blocks move together to the right at a constant acceleration, preventing the smaller block from sliding due to static friction between the blocks. The challenge is to find the correct static friction coefficient required for this setup.
Transcribed Image Text:### Problem Description: A large block is being pushed against a smaller block such that the smaller block remains elevated while being pushed. The mass of the smaller block is \( m = 0.65 \, \text{kg} \). It is found through repeated experimentation that the blocks need to have a minimum acceleration of \( a = 12 \, \text{m/s}^2 \) in order for the smaller block to remain elevated and not slide down. What is the coefficient of static friction \( \mu_s \) between the two blocks? #### Calculation: A user attempted to calculate the coefficient of static friction and entered: \[ \mu_s = 1.22 \] This answer was marked as Incorrect. ### Diagram Explanation: The diagram on the right shows: - A horizontal surface. - A large block is shown in green with a smaller block on top of it to the right, labeled with mass \( m \). - An arrow labeled \( \vec{a} \) points to the right, indicating the direction of acceleration. This setup demonstrates that the blocks move together to the right at a constant acceleration, preventing the smaller block from sliding due to static friction between the blocks. The challenge is to find the correct static friction coefficient required for this setup.
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