A block slides on a surface when two forces act on it as shown in the figure. The two forces acting on it each have magnitude F = 50.0 N and M = 20.0 kg, and coefficient of kinetic friction is 0.20. a. Find the net force in the vertical direction b. Find the net force in the horizontal direction c. What is the magnitude of the resulting acceleration of the block? 30°

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### Problem Description

A block slides on a surface when two forces act on it as shown in the figure. The two forces acting on it each have a magnitude of \( F = 50.0 \, \text{N} \) and the mass of the block \( M = 20.0 \, \text{kg} \). The coefficient of kinetic friction is 0.20.

#### Questions:

a. Find the net force in the vertical direction.

b. Find the net force in the horizontal direction.

c. What is the magnitude of the resulting acceleration of the block?

### Diagram Explanation

The diagram shows a block with mass \( M \) positioned on a horizontal surface. Two forces of equal magnitude \( F \) are acting on the block. One force is directed at an angle of \( 30^\circ \) to the horizontal surface on the left side of the block. The other force is directed horizontally towards the right side of the block. 

The force acting at an angle can be decomposed into two components: one vertical and one horizontal. The coefficient of kinetic friction between the block and surface is used to calculate the frictional force.

### Analysis

- **Vertical Direction:** Analyze the vertical components of the forces acting on the block due to gravity and the vertical component of \( F \).
  
- **Horizontal Direction:** Consider the horizontal components of the forces and the opposing frictional force.

- **Acceleration Calculation:** Use Newton’s second law to find the block's acceleration.

### Key Formulas

- **Decomposition of Forces:** 
  - \( F_{\text{horizontal}} = F \cos(30^\circ) \)
  - \( F_{\text{vertical}} = F \sin(30^\circ) \)

- **Frictional Force:**
  - \( f_k = \mu_k N \)

- **Newton’s Second Law:**
  - \( F_{\text{net}} = ma \)

This problem involves applying principles of physics related to force decomposition, friction, and motion on a horizontal plane.
Transcribed Image Text:### Problem Description A block slides on a surface when two forces act on it as shown in the figure. The two forces acting on it each have a magnitude of \( F = 50.0 \, \text{N} \) and the mass of the block \( M = 20.0 \, \text{kg} \). The coefficient of kinetic friction is 0.20. #### Questions: a. Find the net force in the vertical direction. b. Find the net force in the horizontal direction. c. What is the magnitude of the resulting acceleration of the block? ### Diagram Explanation The diagram shows a block with mass \( M \) positioned on a horizontal surface. Two forces of equal magnitude \( F \) are acting on the block. One force is directed at an angle of \( 30^\circ \) to the horizontal surface on the left side of the block. The other force is directed horizontally towards the right side of the block. The force acting at an angle can be decomposed into two components: one vertical and one horizontal. The coefficient of kinetic friction between the block and surface is used to calculate the frictional force. ### Analysis - **Vertical Direction:** Analyze the vertical components of the forces acting on the block due to gravity and the vertical component of \( F \). - **Horizontal Direction:** Consider the horizontal components of the forces and the opposing frictional force. - **Acceleration Calculation:** Use Newton’s second law to find the block's acceleration. ### Key Formulas - **Decomposition of Forces:** - \( F_{\text{horizontal}} = F \cos(30^\circ) \) - \( F_{\text{vertical}} = F \sin(30^\circ) \) - **Frictional Force:** - \( f_k = \mu_k N \) - **Newton’s Second Law:** - \( F_{\text{net}} = ma \) This problem involves applying principles of physics related to force decomposition, friction, and motion on a horizontal plane.
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