A lamina V of uniform mass density and total mass M kilograms occupies the region between y = l - x 2 and the x-axis (with distance measured in meters). Calculate the rotational kinetic energy if V rotates with angular velocity w = 4 radians per second about: (a) the x-axis. (b) the z-axis.

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A lamina V of uniform mass density and total mass M kilograms occupies the region between y = l - x 2 and the x-axis (with distance measured in meters). Calculate the rotational kinetic energy if V rotates with angular velocity w = 4 radians per second about:
(a) the x-axis. (b) the z-axis.

Expert Solution
Step 1

The curve y=1-x2 gives a parabola with vertex at (0,1) and is downward facing. The parabola intersects the x axis at x=±1. The lamina V is shown shaded in the figure.

Advanced Physics homework question answer, step 1, image 1

Step 2

The rotational kinetic energy of a rotating object is given by,

KErot=12Iω2

where I is the moment of inertia of the object about the rotation axis and ω is its angular velocity.

Given,

Total mass of the lamina = M kg

Angular velocity ω=4 rad s-1

To solve this question we need to find out the moments of inertia about the axis in question.

Step 3

(a) Calculation of moment of inertia of the lamina about the x axis.

Moment of inertia is given as,

I=r2dm

where r is the distance of elementary mass dm from the axis of rotation. In this case the axis of rotation is the x axis.

Let us define the mass per unit area of the lamina as σ i.e.

σ=MA

where A is the total area of the lamina which is calculated as,

A=201ydx=2011-x2dx=21-13=43 m2

Thus, σ=3M4 kgm-2

Step 4

The moment of inertia is calculated as shown in the figure below

Advanced Physics homework question answer, step 4, image 1

dm=2σxdy

So,

dI=dm y2I=y2dm=201σxy2dy=2σ01y21-ydy

On integrating, it comes out to be,

Ix=8M35 kg m2

Step 5

The rotational kinetic energy of the lamina when it rotates about the x axis is,

KErot=12Ixω2=128M3542=64M35 J

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