A jet flying at 136 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2.08 × 105 kg. Calculate the magnitude of the necessary lifting force. L = i ✪
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
![### Example Problem: Calculating Lifting Force in a Horizontal Circular Turn
#### Problem Statement:
A jet flying at 136 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is \(2.08 \times 10^5\) kg. Calculate the magnitude of the necessary lifting force.
#### Given Data:
- Speed of the jet, \( v = 136 \, \text{m/s} \)
- Radius of the turn, \( r = 3810 \, \text{m} \)
- Mass of the jet, \( m = 2.08 \times 10^5 \, \text{kg} \)
#### Calculate:
The necessary lifting force, \( L \)
#### Solution Input:
\[ L = \, \text{(input box)} \]
The lifting force can be calculated using the centripetal force formula needed to maintain the horizontal circular motion:
\[ F_{\text{centripetal}} = \frac{m \cdot v^2}{r} \]
Since the lifting force must counteract this centripetal force:
\[ L = \frac{m \cdot v^2}{r} \]
#### Step-by-step Calculation:
1. Substitute the given values into the centripetal force formula:
\[ L = \frac{2.08 \times 10^5 \, \text{kg} \cdot (136 \, \text{m/s})^2}{3810 \, \text{m}} \]
2. Solve for \( L \):
Input fields are present for students to perform the calculations and input their answers.
This example helps in understanding the application of the centripetal force concept in physics problems involving circular motion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30341bd5-9df6-4a1f-8fda-916b6928e177%2Fc12a0f4f-eb94-49c0-9b09-e56a40978e37%2Fa8nbnh_processed.jpeg&w=3840&q=75)
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