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a) In the generator zone, Vbasel 480 V and Sbase = 10 kVA hence: Sbase Ibasel V base1 ● = - 10,000 VA 480 V Zbasel = 20.83 A V base1 Ibase1 480 V 20.83 A = 23.04 Ω 480 20⁰ V 10 kVA VG Zone 1 1:10 20 £2 Z j60 £2 Zone 2 20:1 Laad Zone 3 Zand 10 230°

a) In the generator zone, Vbasel 480 V and Sbase = 10 kVA hence: Sbase Ibasel V base1 ● = - 10,000 VA 480 V Zbasel = 20.83 A V base1 Ibase1 480 V 20.83 A = 23.04 Ω 480 20⁰ V 10 kVA VG Zone 1 1:10 20 £2 Z j60 £2 Zone 2 20:1 Laad Zone 3 Zand 10 230°

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) In the generator zone, V. Ibasel ● Spase V base1 10,000 VA 480 V Zbasel = 20.83 A V base1 Ibase1 480 V 20.83 A = 23.04 Ω basel = 480 V and Sbase = 10 kVA hence: 4800⁰ V 10 kVA Vo G Zone 1 ● 1:10 20 £2 Z j60 £2 Zone 2 20:1 I Load Zone 3 Zaad 10 4 30° Ω
Transcribed Image Text:a) In the generator zone, V. Ibasel ● Spase V base1 10,000 VA 480 V Zbasel = 20.83 A V base1 Ibase1 480 V 20.83 A = 23.04 Ω basel = 480 V and Sbase = 10 kVA hence: 4800⁰ V 10 kVA Vo G Zone 1 ● 1:10 20 £2 Z j60 £2 Zone 2 20:1 I Load Zone 3 Zaad 10 4 30° Ω
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