Q2/A- implement 32KX 16 EPROM using 8KX8 EPROM Ic's and 2:4 decoder?B- Design microprocessor 8086 memory system consisting of 1M byte, using• 128K*8 memory chips2:4 decoder chips that have two enable lines one active high and the other active low• control line signal that 8086 microprocessor provided it in minimum mode

A. Total number of 8Kx8 ROM chips required = 32Kx16/8Kx8 = 4x2 = 8 These 8 chips are stored as…

Answered: A- implement 32K* 16 EPROM using 8K*8…

A- implement 32K* 16 EPROM using 8K*8 EPROM IC's and 2:4 decoder? B- Design microprocessor 8086 memory system consisting of 1M byte, using 129Kx8 memoni chine

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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microprocessor 8086
The MSP430F20x is a microcontroller with 64 KiB of address space divided between code memory (flash), RAM memory, and input/output peripherals. It has 2,048 Bytes of RAM memory starting at the address 0x0200, and 256 Bytes of address space reserved for special purpose registers and 8-bit input/output peripherals (starting at the address 0x0000) followed by 256 Bytes reserved for 16-bit input/output peripherals. The flash memory of 16 KiB resides at the top of address space (highest addresses in the address space). C. Determine the address map by filling in the following table. Address Byte Address (hexadecimal) Sections in address space Last Flash Address Flash Memory First Flash Address Flash Memory Last RAM address RAM Memory First RAM address RAM Memory Last I/O address (16-bit per.) I/O address space First I/O address (16-bit per.) Last I/O address (8-bit per.) I/O address space First I/O address (8-bit per.) D. What is the maximum stack…
Draw a block diagram of a microprocessor based system interfaced with 8237and RAMAlso show clock generator, buffers, transceivers and address decoder in the diagram: use 8088 in maximum mode
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Add Add Sum 1 Shift left 1 Branch MemRead Instruction [6-0] MemtoReg ALUOP Control MemWrite ALUSCC RegWrite L3 Instruction [19-15] Read address Read register 1 PC Instruction (24-20] Read data 1 Instruction [31-0] Read register 2 Zero ALU ALU Read Instruction [11-7) Read data 2 Address Write result data Instruction register memory Write data Registers Write Data data memoryl Instruction (31-0) 32 Imm 64 ALU Gen control Instruction [30,14-12] During a particular clock cycle, consider the CPU shown in the drawing. Assume that the following initial data is present (all values are shown in decimal, DM is Data Memory): x8=72. x18=56, DM(64) =48 During the cycle in question, assume that the following instruction is executed (the first column is the instruction's address: all values are shown in decimal): 51868 Id x8.8(x18) Write below the value of the bus L1 in decimal: L1 Write below the value of the bus L2 in decimal: L2 Write below the value of the bus L3 in decimal: L3
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ISA of a hypothetical CPU 1 Address Memory: Address Data - (8-bits) LOAD M 100 25 STORE M 101 90 ADD M 102 65 SUB M 103 36 MUL M 104 22 105 77 DIV M 106 89 Where: Note: all numbers are hexadecimal M-a memory address AC - accumulator Sample program: //line 1 /line 2 //line 3 //line 4 //line 5 //line 6 LOAD 100 ADD 101 STORE 106 LOAD 102 SUB 103 STORE 105 Answer the following questions based on the given information above. 1. What is the content of memory location 106 after executing line 3? 2. What is the content of memory location 105 after executing line 6? 3. Write a program segment that will multiply the content of memory location 105 with the content of AC and store the result at memory location 100. а. b. 4. For this CPU, what is the width of the program counter? (express answer in terms of bits, do not include the word "bits" in your answer)
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