(a) If an FEV of less than 2.5 L is regarded as showing some functional impairment (occasional breathlessness, inability to climb stairs, etc.), then what is the probability that a currently smoking man has functional impairment? 0.0099 You may have rounded in the wrong direction. (b) What is the probability that a currently nonsmoking man has functional impairment? 0.0007 Some people are not functionally impaired now, but their pulmonary function usually declines with age and they eventually will be functionally impaired. Assume that the decline in FEV over n years is normally distributed, with mean = 0.03n L and standard deviation 0.02n L. (Assume that FEV can be measured exactly and no continuity correction is necessary. Round your answers to four decimal places.) (c) What is the probability that a 49-year-old man with an FEV of 4.1 L will be functionally impaired by age 85? 0.2180 (d) What is the probability that a 35-year-old man with an FEV of 4.1 L will be functionally impaired by age 85. 0.5000 See the rounding prompt for how many decimal places are needed.
(a) If an FEV of less than 2.5 L is regarded as showing some functional impairment (occasional breathlessness, inability to climb stairs, etc.), then what is the probability that a currently smoking man has functional impairment? 0.0099 You may have rounded in the wrong direction. (b) What is the probability that a currently nonsmoking man has functional impairment? 0.0007 Some people are not functionally impaired now, but their pulmonary function usually declines with age and they eventually will be functionally impaired. Assume that the decline in FEV over n years is normally distributed, with mean = 0.03n L and standard deviation 0.02n L. (Assume that FEV can be measured exactly and no continuity correction is necessary. Round your answers to four decimal places.) (c) What is the probability that a 49-year-old man with an FEV of 4.1 L will be functionally impaired by age 85? 0.2180 (d) What is the probability that a 35-year-old man with an FEV of 4.1 L will be functionally impaired by age 85. 0.5000 See the rounding prompt for how many decimal places are needed.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Pulmonary Disease
Forced expiratory volume (FEV) is an index of pulmonary function that measures the volume of air expelled after 1 second of constant effort. FEV is influenced by age, sex, and cigarette smoking.
Assume that in 45- to 54-year-old nonsmoking men FEV is normally distributed with mean = 4.1 L and standard deviation
0.5 L.
In comparably aged currently smoking men FEV is normally distributed, with mean = 3.9 L and standard deviation = 0.6 L. (Assume that FEV can be measured exactly and no continuity correction is
necessary. Round your answers to four decimal places.)
In USE SALT
(a) If an FEV of less than 2.5 L is regarded as showing some functional impairment (occasional breathlessness, inability to climb stairs, etc.), then what is the probability that a currently smoking
man has functional impairment?
0.0099
You may have rounded in the wrong direction.
(b) What is the probability that a currently nonsmoking man has functional impairment?
0.0007
Some people are not functionally impaired now, but their pulmonary function usually declines with age and they eventually will be functionally impaired. Assume that the decline in FEV over n years is
normally distributed, with mean = 0.03n L and standard deviation 0.02n L. (Assume that FEV can be measured exactly and no continuity correction is necessary. Round your answers to four decimal
places.)
(c) What is the probability that a 49-year-old man with an FEV of 4.1 L will be functionally impaired by age 85?
0.2180
(d) What is the probability that a 35-year-old man with an FEV of 4.1 L will be functionally impaired by age 85.
0.5000
See the rounding prompt for how many decimal places are needed.
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