K A dairy farmer chooses between two types of food for his small herd of cows. Let x be the number of pounds of alfalfa hay and y be the number of pounds of ground ears of corn to be bought. How many pounds of each food should be purchased in order to meet the nutritional requirements at the least cost, if the objective function is x + 1.5y? (See the graph of the feasible set on the right.) 80,000 39,500 x= 19,000 feasible set y= -2x+80,000 y= -0.5x+39,500 X 40,000 79,000 מ
K A dairy farmer chooses between two types of food for his small herd of cows. Let x be the number of pounds of alfalfa hay and y be the number of pounds of ground ears of corn to be bought. How many pounds of each food should be purchased in order to meet the nutritional requirements at the least cost, if the objective function is x + 1.5y? (See the graph of the feasible set on the right.) 80,000 39,500 x= 19,000 feasible set y= -2x+80,000 y= -0.5x+39,500 X 40,000 79,000 מ
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The number of pounds of alfalfa hay, x, is equal to
The number of pounds of ground ears of corn, y, is equal to
Transcribed Image Text:K
A dairy farmer chooses between two types of food for his small herd of cows. Let x be the number
of pounds of alfalfa hay and y be the number of pounds of ground ears of corn to be bought. How
many pounds of each food should be purchased in order to meet the nutritional requirements at
the least cost, if the objective function is x + 1.5y? (See the graph of the feasible set on the right.)
80,000
39,500
x= 19,000
feasible
set
y= -2x+80,000
y= -0.5x+39,500
X
40,000
79,000
מ
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