A human resources director wants to determine if there is a dependence between day of the week and the number of times employees took sick leave on that day. Open Sick Leave (- Click on link). Test HO: Monday = Tuesday = Wednesday = Thursday Friday = Saturday. Keep your Excel file open for the following 3 questions. The chi square statistic is %3D %3D %3D OA) .82 O B) .80 OC) .81 D) .83

A human resources director wants to determine if there is a dependence between day of the week and the number of times employees took sick leave on that day. Open Sick Leave (- Click on link). Test HO: Monday = Tuesday = Wednesday = Thursday Friday = Saturday. Keep your Excel file open for the following 3 questions. The chi square statistic is %3D %3D %3D OA) .82 O B) .80 OC) .81 D) .83

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Explain MEAN SQUARES (M S) AND F RATIOS.
A recent study evaluated how addicted teenagers become to nicotine once they start smoking. The response variable was the number of yes answers on a questionnaire called the Hooked on Nicotine Checklist (HONC). Of teenagers who had tried tobacco, the mean HONC score was 4.2 (s = 5.4) for the 149 females and 2.8 (s=4.2) for the 190 males. Complete parts a through c below. 000 DOD F4 What does the standard error indicate? A. The standard error describes the spread of the sampling distribution of x₁ - x₂. B. The standard error is the standard deviation of the difference between x₁ - x₂. OC. The standard error is the standard deviation of the sample for this study. OD. The standard error is the difference in standard deviations for the two populations. ... b. Find the test statistic and P-value for Ho: H₁ H₂ and Ha: H₁ H₂. Interpret, and explain what (if any) effect gender has on the mean HONC score. Use the significance level 0.05. The test statistic is (Round to two decimal places as…
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HAV is a deformation of the big toe that often requires surgery. Doctors used X-rays to measure the angle (in degrees) of deformity in 38 consecutive patients under the age of 21 who came to a medical center for surgery to correct HAV. The angle is a measure of the seriousness of the deformity. Here are the data. 292216 321828 231529 352322 372249 261623 263328 202530 321933 242138 262230 112023 2124 It is reasonable to regard these patients as a random sample of young patients who require HAV surgery. Given a 95% confidence interval for the mean HAV angle in the population of all such patients, find the following. x (mean) = s=(standard deviation) = Confidence Interval: ° to ° Conclusion 1) We are 95% confident that the mean HAV angle among such patients is within this interval. 2) We are 95% confident that the mean HAV angle among such patients is outside this interval. 3) The mean HAV angle among such patients will always be outside this interval 95% of…