Suppos are interested in studying a population to estimate its mean. The population is normal and has a standard deviation of G=23. We have taken arandom sample of size 11=95 from the population. This is Sample 1 in the table below. (In the table, Sample 1 is written "S1", Sample 2 is written "S2", etc.)As shown in the table, the sample mean of Sample 1 is = 142.0. Also shown are the lower and upper limits of the 80% confidence interval for the populationmean using this sample, as well as the lower and upper limits of the 95% confidence interval. Suppose that the true mean of the population is = 140, which isshown on the displays for the confidence intervals.Press the "Generate Samples" button to simulate taking 19 more random samples of size 11 = 95 from this same population. (The 80% and 95% confidenceintervals for all of the samples are shown in the table and graphed.) Then complete parts (a) through (c) below the table.80% 80% 95% 95%lower upper lower upperlimit limit limit limits1 142.0 139.3 144.7 137.4 146.652 141.2 138.5 143.9 136.6 145.853 140.9 138.2 143.6 136.3 145.554 141.2 138.5 143.9 136.6 145.8S5 139.0 136.3 141.7 134.4 143.656 143.6 140.9 146.3 139.0 148.257 141.7 139.0 144.4 137.1 146.358 139.7 137.0 142.4 135.1 144.359 136.5 133.8 139.2 131.9 141.1sio|1415|133.3|1442|1369|1461511|1452|142.3|1479|1406|149.8s12 138.5 135.8 141.2 133.9 143.1S13 136.4 133.7 139.1 131.8 141.0S14 139.9 137.2 142.6 135.3 144.5515143.6| 140.9 | 1463 | 139.0|1482s16 141.8 139.1 144.5 137.2 146.4s17 139.6 136.9 142.3 135.0 144.2s18 134.7 132.0 137.4 130.1 139.3S19 140.2 137.5 142.9 135.6 144.8s20 141.5 138.8 144.2 136.9 146.1130.080% confidence intervalsF150.0 130.095% confidence intervals150.0(a) How many of the 80% confidence intervals constructed from the 20 samples contain the population mean, y = 140?(b) How many of the 95% confidence intervals constructed from the 20 samples contain the population mean, μ = 140?(c) Choose ALL that are true.The center of the 80% confidence interval for Sample 1 is 142.0, because the center of a confidence interval for thepopulation mean must be the sample mean.All of the 95% confidence intervals should be the same as each other. Since they are not all the same, there musthave been errors due to rounding.Since Sample 19 and Sample 20 are drawn from the same population, the center of the 95% confidence interval forSample 19 must be the same as the center of the 95% confidence interval for Sample 20.For each sample, the 80% confidence interval for the sample is included in the 95% confidence interval for thesample.None of the choices above are true.Español?BA

Answered: (a) How many of the 80% confidence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Repeat the analysis of the clinical study in Example 4.4.8 on page 155 using a confidence level of 95%. What conclusion can you draw about the effectiveness of the drug?
1q
In random, independent samples of 400 adults and 275 teenagers who watched a certain television show, 224 adults and 121 teens indicated that they liked the show. Let p, be the proportion of all adults watching the show who liked it, and let p, be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for p,-P2. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least three decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 115, and the sample standard deviation, s, is found to be 10. (a) Construct an 80% confidence interval about μ if the sample size, n, is 25. (b) Construct an 80% confidence interval about μ if the sample size, n, is 12. (c) Construct a 70% confidence interval about μ if the sample size, n, is 25. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?
Professor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the mean score of the population? What is the mean score of the sample? Is this test one-tailed or two-tailed? Why?
A random sample of small-business managers was given a leadership style questionnaire. The results were scaled so that each manager received a score for initiative. Suppose the following data are a random sample of these scores. 37 42 43 39 38 31 43 37 35 45 30 33 35 44 36 37 39 33 39 43 41 33 35 36 41 33 37 38 43 42 44 35 36 33 38 32 30 37 42 Assuming σ is 4.210, use these data to construct a 90% confidence interval to estimate the average score on initiative for all small-business managers. Appendix A Statistical Tables (Round the intermediate values to 3 decimal places, e.g. 25.316. Round your answers to 3 decimal places, e.g. 25.316.)enter the lower value of the interval ≤ μ ≤ enter the upper value of the interval
Question 1: The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing students, 75% were placed on honor roll. Of a sample of 100 athletes, 80% of the students were placed on honor roll. Calculated the LOWER bound of the 95% confidence interval for the two samples. Round to the nearest hundredth. Question 2: The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing students, 75% were placed on honor roll. Of a sample of 100 athletes, 80% of the students were placed on honor roll. Calculated the UPPER bound of the 95% confidence interval for the two samples. Round to the nearest hundredth. Question 3: Copy of The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing…
Suppose we are interested in studying a population to estimate its mean. The population is normal and has a standard deviation of o=9. We have taken a random sample of size n = 60 from the population. This is Sample 1 in the table below. (In the table, Sample 1 is written "S1", Sample 2 is written "S2", etc.) As shown in the table, the sample mean of Sample 1 is x = 81.1. Also shown are the lower and upper limits of the 75% confidence interval for the population mean using this sample, as well as the lower and upper limits of the 95% confidence interval. Suppose that the true mean of the population is μ = 80, which is shown on the displays for the confidence intervals. Press the "Generate Samples" button to simulate taking 19 more random samples of size n = 60 from this same population. (The 75% and 95% confidence intervals for all of the samples are shown in the table and graphed.) Then complete parts (a) through (c) below the table. 75% 75% 95% 95% lower upper lower limit limit limit…
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 110, and the sample standard deviation, s, is found to be 10. (a) Construct a 95% confidence interval about µ if the sample size, n, is 24. (b) Construct a 95% confidence interval about µ if the sample size, n, is 16. p (c) Construct a 90% confidence interval about if the sample size, n, is 24. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 24. Lower bound: Upper bound www
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 110, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 15. (b) Construct a 98% confidence interval about μ if the sample size, n, is 24. (c) Construct a 99% confidence interval about μ if the sample size, n, is 15. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, ×, is found to be 110, and the sample standard deviation, s, is found to be 8. (a) Construct a 99% confidence interval about u if the sample size, n, is 24. (b) Construct a 99% confidence interval about u if the sample size, n, is 13. (c) Construct a 96% confidence interval about u if the sample size, n, is 24. (d) Should the confidence intervals in parts (a)(c) have been computed if the population had not been normally distributed? An example was provided with additional pictures.
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 111, and the sample standard deviation, s, is found to be 9. (a) Construct a 98% confidence interval about u if the sample size, n, is 24. (b) Construct a 98% confidence interval about if the sample size, n, is 17. (c) Construct a 90 confidence interval about ji if the sample size, n, is 24. (d) Should the confidence intervals in parts (a)-(c) have been computed if the population had not been normally distributed? (a) Construct a 98% confidence interval about p if the sample size, n, is 24. Lower bound 105.8 Upper bound: 162 (Round to one decimal place as needed.)

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