A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 106, and the sample standard deviation, s, is found to be 10.(a) Construct a 90% confidence interval about u if the sample size, n, is 18(b) Construct a 90% confidence interval about u if the sample size, n, is 22.(c) Construct a 96% confidence interval about u if the sample size, n, is 18.(d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?E Click the icon to view the table of areas under the t-distribution.(a) Construct a 90% confidence interval about u if the sample size, n, is 18.Lower bound: 101.9 ; Upper bound: 110.1(Use ascending order. Round to one decimal place as needed.)(b) Construct a 90% confidence interval about u if the sample size, n, is 22.Lower bound: 102.3 : Upper bound: 109.7(Use ascending order. Round to one decimal place as needed.)How does increasing the sample size affect the margin of error, E?A. As the sample size increases, the margin of error decreases.O B. As the sample size increases, the margin of error increases.O C. As the sample size increases, the margin of error stays the same.(c) Construct a 96% confidence interval about u if the sample size, n, is 18.Lower bound: Upper bound:(Use ascending order. Round to one decimal place as needed.)Clear allTutoringHelp me solve thisGet more help-MacBook ProG Search or type URLesc$%&!@%2346.1WERYQKFGつエヒ

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Answered: C. As the sample size increases, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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C. As the sample size increases, the margin of error stays the same. (c) Construct a 96% confidence interval about u if the sample size, n, is 18. Lower bound:: Upper bound: (Use ascending order. Round to one decimal place as needed.)