A hot water pipe that is used for domestic applications of 0.12 m outside diameter is insulated with a layer of calcium silicate. If the insulation is 20 mm thick and its inner and outer surfaces are maintained at T= 800 K and T,2= 490 K, respectively (a) What is the heat loss per unit length (q') of the pipe?

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A hot water pipe that is used for domestic applications of 0.12 m outside diameter is insulated with
a layer of calcium silicate. If the insulation is 20 mm thick and its inner and outer surfaces are
maintained at T,1= 800 K and T32= 490 K, respectively
(a)
What is the heat loss per unit length (q') of the pipe?
(b)
Explore the effect of insulation thickness on the heat loss q' and outer surface temperature
T32 with the inner surface temperature being fixed at 800 K. The outer surface is exposed to
moving airflow (T= 25°C) that maintains a convection coefficient of 25 W/m2 K and to large
surroundings for which Taus= T= 25°C. The surface emissivity of calcium silicate is
approximately 0.9.
Compute and plot the temperature distribution in the insulation material as a function of the radial
rzceordinate, where n = 0.06 m and 12 has a range of (0.06< 1, <0.2 m).
Compute and plot the r2 -r1
heat loss as a function of the insulation thickness for 0< (12 - 1) <0.14 m. Given the thermal
conductivity of calcium silicate insulation equals to 0.089 W/m.K.
Transcribed Image Text:A hot water pipe that is used for domestic applications of 0.12 m outside diameter is insulated with a layer of calcium silicate. If the insulation is 20 mm thick and its inner and outer surfaces are maintained at T,1= 800 K and T32= 490 K, respectively (a) What is the heat loss per unit length (q') of the pipe? (b) Explore the effect of insulation thickness on the heat loss q' and outer surface temperature T32 with the inner surface temperature being fixed at 800 K. The outer surface is exposed to moving airflow (T= 25°C) that maintains a convection coefficient of 25 W/m2 K and to large surroundings for which Taus= T= 25°C. The surface emissivity of calcium silicate is approximately 0.9. Compute and plot the temperature distribution in the insulation material as a function of the radial rzceordinate, where n = 0.06 m and 12 has a range of (0.06< 1, <0.2 m). Compute and plot the r2 -r1 heat loss as a function of the insulation thickness for 0< (12 - 1) <0.14 m. Given the thermal conductivity of calcium silicate insulation equals to 0.089 W/m.K.
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